11.07.2015 Views

Elliptic Modular Forms and Their Applications - Up To

Elliptic Modular Forms and Their Applications - Up To

Elliptic Modular Forms and Their Applications - Up To

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

40 D. Zagierler product L(f,s) =∏ ( a p 1+p prime p s + a p 2p 2s + ···), <strong>and</strong> the second tells usthat the power series ∑ ∞ν=0 a p ν xν for p prime equals 1/(1 − a p x + p k−1 x 2 ).Combining these two statements gives Hecke’s fundamental Euler productdevelopmentL(f,s) =∏11 − a p p −s + p k−1−2s (44)p primefor the L-series of a normalized Hecke eigenform f ∈ M k (Γ 1 ),asimpleexamplebeing given byL(G k ,s) = ∏ p11 − (p k−1 +1)p −s = ζ(s) ζ(s − k +1).+ pk−1−2s For eigenforms on Γ 0 (N) there is a similar result except that the Euler factorsfor p|N have to be modified suitably.The L-series have another fundamental property, also discovered by Hecke,which is that they can be analytically continued in s <strong>and</strong> then satisfy functionalequations. We again restrict to Γ = Γ 1 <strong>and</strong> also, for convenience, tocusp forms, though not any more just to eigenforms. (The method of proof extendsto non-cusp forms but is messier there since L(f,s) then has poles, <strong>and</strong>since M k is spanned by cusp forms <strong>and</strong> by G k ,whoseL-series is completelyknown, there is no loss in making the latter restriction.) From the estimatea n = O(n k/2 ) proved in §2.4 we know that L(f,s) converges absolutely in thehalf-plane R(s) > 1+k/2. Takes in that half-plane <strong>and</strong> consider the Eulergamma function∫ ∞Γ (s) = t s−1 e −t dt .0Replacing t by λt in this integral gives Γ (s) =λ ∫ s ∞t s−1 e −λt dt or λ −s =0Γ (s) ∫ −1 ∞t s−1 e −λt dt for any λ>0. Applying this to λ =2πn, multiplying0by a n , <strong>and</strong> summing over n, weobtain(2π) −s Γ (s) L(f,s) =∞∑∫ ∞a n t s−1 e −2πnt dt = t s−1 f(it) dt00(R(s) > k )2 +1 ,n=1∫ ∞where the interchange of integration <strong>and</strong> summation is justified by the absoluteconvergence. Now the fact that f(it) is exponentially small for t →∞(because f is a cusp form) <strong>and</strong> for t → 0 (because f(−1/z) =z k f(z) )impliesthat the integral converges absolutely for all s ∈ C <strong>and</strong> hence that thefunctionL ∗ (f,s) := (2π) −s Γ (s) L(f,s) = (2π) −s Γ (s)∞∑n=1a nn s (45)

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!