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On Node Ranking of Graphs under Strong Orientation

On Node Ranking of Graphs under Strong Orientation

On Node Ranking of Graphs under Strong Orientation

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The 24th Workshop on Combinatorial Mathematics and Computation TheoryW1,8W1,81321W 1,8132 11221535122112411241Figure 1: <strong>Node</strong> ranking labelings on undirected and strong orientations <strong>of</strong> W1,8.2 Main resultsLemma 1: [2] The node ranking number <strong>of</strong> a cycleCnis r( Cn) lgn 1.Since the only strong orientation <strong>of</strong> a cycle iseither a clockwise or counterclockwise directed cycle,by lemma 1, theorem 2 comes trivial.Lemma 2: Let G Cnbe a cycle on n vertices.Then the upper and lower node ranking numberRANK( G) rank( G) lgn 1.Given H be a subgraph <strong>of</strong> G, since every u-v path inH must be a u-v path in G, but not the reverse, wehave following proposition:Proposition 1: Let H be a subgraph <strong>of</strong> G. Then ( H ) ( G).rrSimilar to the undirected graph, digraphs have thesame proposition which is stated as proposition 2.Proposition 2: Let H be a subgraph <strong>of</strong> D. Then( H ) ( D).rrLemma 3: The node ranking number <strong>of</strong> a wheelW1,nis r( W1,n) lgn 2.Pro<strong>of</strong>Let vcdenote the center vertex <strong>of</strong> W1,nandV { v , v ,..., v } denote the vertices on the cycle <strong>of</strong>n1 2nthe wheel. To see that r( W1,n) lgn 2,suppose to the contrary, r( W1,n) lgn 1. LetC: V( W1,n) 1,2, , lgn1be an optimal noderanking labeling <strong>of</strong> W1,n. Since v cis adjacent tovifor all v i V n, we have Cv (c) Cv (i),vi Vn.Since every pair <strong>of</strong> vertices v , v withijCv (i) Cv (j), vi-vc-v jis a path in W 1,n, withoutloss <strong>of</strong> generality, we may have Cv (c) lgn1which implies Cv (i) lgn for all vi Vn.Consider the subgraph Cn W1,n vc, letC : V( Cn) 1,2, , lgnbe a labeling definedas C( vi) C( vi)for all v i V n. Then C is anode ranking labeling <strong>of</strong> C nwith maximum ranklg n , which implies r( Cn) lgn contradictsto Lemma 1. Hence r( W1,n) lgn 2. Nowconsider a labeling f : V( W1,n) 1,2, lgn2 which labels Vn { v1, v2,..., vn} by an optimalnode ranking labeling <strong>of</strong> C and labels the vertexvcas lg n 2 . Then f is a node ranking labeling<strong>of</strong> W1,nwith maximum rank lg n 2 whichimplies r( W1,n) lgn 2. Hence we haver( W1,n) lgn 2. Since each directed path P in a strong orientation D<strong>of</strong> graph G is a path in G, if f is an optimal noderanking <strong>of</strong> D then f must be a node ranking labeling<strong>of</strong> G. Hence we have proposition 3 as follows.Proposition 3: Let G be a graph and D be anorientation <strong>of</strong> G. Then ( D) ( G).Since the adjacent vertices may not have the samerank, lemma 4 is trivial.Lemma 4: The node ranking number <strong>of</strong> completegraph is r( Kn) n . For any tournament D withn vertices, r( D) n .Lemma 5: [8] Le G be a graphC: V( G) {1,2, k}be an optimal node rankinglabeling <strong>of</strong> G . Then i,1i k , there is a vertexv V( G)such that Cv () i.rnr-423-

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