Chapter 5: Exercises with Solutions

Section 5.5Motion13.v (ft/s)5030v150 ft00 5t (s)The distance traveled is the area under the curve, which is a rectangle, so the area islength times width, or d = 30 ft s × 5 s = 150 ft.15.v (m/s)40v20100 m00 5t (s)The distance traveled is the area under the curve, which is a triangle. The formula forarea of a triangle is 1 × base × height, so2d = 1 × base × height2= 1 2 × 5 s × 40m s= 100 mVersion: Fall 2007