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Chapter 5: Exercises with Solutions

Chapter 5: Exercises with Solutions

Chapter 5: Exercises with Solutions

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498 <strong>Chapter</strong> 5 Quadratic Functions22. f(x) = −x 2 − 8x − 823. f(x) = −x 2 − 8x − 924. f(x) = −x 2 + 10x − 2025. f(x) = 2x 2 − 20x + 4026. f(x) = 2x 2 − 16x + 1227. f(x) = −2x 2 + 16x + 828. f(x) = −2x 2 − 24x − 52In <strong>Exercises</strong> 29-32, perform each of thefollowing tasks for the given quadraticequation.i. Set up a coordinate system on a sheetof graph paper. Label and scale eachaxis. Remember to draw all lines <strong>with</strong>a ruler.ii. Show that the discriminant is negative.iii. Use the technique of completing thesquare to put the quadratic functionin vertex form. Plot the vertex onyour coordinate system and label it<strong>with</strong> its coordinates. Draw the axis ofsymmetry on your coordinate systemand label it <strong>with</strong> its equation.iv. Plot the y-intercept and its mirrorimage across the axis of symmetryon your coordinate system and labeleach <strong>with</strong> their coordinates.v. Because the discriminant is negative(did you remember to show that?),there are no x-intercepts. Use thegiven equation to calculate one additionalpoint, then plot the point andits mirror image across the axis ofsymmetry and label each <strong>with</strong> theircoordinates.vi. Using all of the information on yourcoordinate system, draw the graph ofthe parabola, then label it <strong>with</strong> thevertex form of function. Use intervalnotation to describe the domain andrange of the quadratic function.29. f(x) = x 2 + 4x + 830. f(x) = x 2 − 4x + 931. f(x) = −x 2 + 6x − 1132. f(x) = −x 2 − 8x − 20In <strong>Exercises</strong> 33-36, perform each of thefollowing tasks for the given quadraticfunction.i. Set up a coordinate system on a sheetof graph paper. Label and scale eachaxis. Remember to draw all lines <strong>with</strong>a ruler.ii. Use the discriminant to help determinethe value of k so that the graphof the given quadratic function hasexactly one x-intercept.iii. Substitute this value of k back intothe given quadratic function, then usethe technique of completing the squareto put the quadratic function in vertexform. Plot the vertex on your coordinatesystem and label it <strong>with</strong> itscoordinates. Draw the axis of symmetryon your coordinate system andlabel it <strong>with</strong> its equation.iv. Plot the y-intercept and its mirrorimage across the axis of symmetryand label each <strong>with</strong> their coordinates.v. Use the equation to calculate an additionalpoint on either side of the axisof symmetry, then plot this point andits mirror image across the axis ofsymmetry and label each <strong>with</strong> theircoordinates.vi. Using all of the information on yourcoordinate system, draw the graphof the parabola, then label it <strong>with</strong>the vertex form of the function. UseVersion: Fall 2007

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