11.07.2015 Views

MEMOIRS

MEMOIRS

MEMOIRS

SHOW MORE
SHOW LESS
  • No tags were found...

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

62 3. TUBULAR SHIFTS AND PRIME ELEMENTSProof. Let M ∈H + be of rank r>0. Let S = S x be the simple objectconcentrated in x. There is the universal extension0 −→ M α M−→ σ x (M) −→ Ext 1 (S, M) ⊗ End(S) S −→ 0.The morphism M ·π x−→ M(d) is a monomorphism and its cokernel is concentrated inthe point x and of length r · e(x): using a line bundle filtration of M and induction,it suffices to show this for line bundles L ′ . If L ′ is a shift of L then the cokernelis Sxe(x) . In orbit case III we have to consider also the case L ′ = L. There is anirreducible map L −→ uL, and the cokernel S 0 is a simple object. One can assumethat S 0 ≄ S x . It then follows that the cokernel of the map L ·π x−→ L(d) isalsoisomorphic to Sx e(x) .We have to show that the cokernel C of M ·π x−→ M(d) is semisimple: The mapC ·π x−→ C(d) is zero, which follows from the commutative exact diagram0 M ·π xM(d)·π x·π x (d)0 M(d) ·π x(d)M(2d)p(d)pC·π x0C(d) 0.Applying the exact functor φ ◦ q x from 2.2.6 we get a short exact sequence ofright R P -modules:·π0 −→ MxP −→ M(d)P −→ C P −→ 0.Since the map C ·π x−→ C(d) is zero, we see that C P is a graded R P /P P -module,hence semisimple by 2.2.8. It follows that C is a direct sum of copies of S.Hence we get a commutative, exact diagram0 M α MM(x)β MM x 0i M0 M ·π xM(d)j M0,Cwith isomorphisms i M and j M (compare 0.4.2 (2)). With the uniqueness property0.4.2 (1) of σ x (f) it follows easily that for each f ∈ Hom(M,N)(withN ∈H + )we have σ x (f)◦i M = i N ◦f(d). Therefore, the functors σ d and σ x are naturally isomorphicon H + . (Actually, the argument shows, that this holds everywhere outsideU x .) With Lemma 1.2.2, presenting each object in H 0 as cokernel of a monomorphismbetween objects from H + , the result follows by diagram chasing. □Corollary 3.1.3. Let x, y ∈ X such that the corresponding prime elementsπ x and π y are central of the same degree in R. Then the tubular shifts σ x and σ yare isomorphic.□3.2. Non-central prime elements and ghosts3.2.1 (Normal multiplication). We generalize Theorem 3.1.2 to arbitrary primeelements. Therefore, assume that r ∈ R is a (non-zero) normal element of degree n.Then r induces the automorphism γ = γ r of the graded algebra R, by the formula

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!