Astro 160: The Physics of Stars
Astro 160: The Physics of Stars
Astro 160: The Physics of Stars
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where c n is again a dimensionless function that you should write down. Also show that the centralpressure <strong>of</strong> a polytrope can be written asP c = d n GM 2/3 ρ 4/3cwhere d n depends on a n and c n . <strong>The</strong> values <strong>of</strong> a n ,d n , and d n can be determined by numerically solving theLane-Emden equation. <strong>The</strong> most useful cases for our purposes are γ = 4/3 (n = 3) and γ = 5/3 (n = 3/2)polytropes. For n = 1.5, a n = 5.99 and c n = 0.77 while for n = 3, a n = 54.183 and c n = 11.05. We will usethese quite a bit during this course. Note how, as mentioned in class, the results for the central pressure anddensity <strong>of</strong> polytropes above are very similar to what you would get from an order <strong>of</strong> magnitude estimate,except that for polytropes we get an exact correct numerical factor given by a n , c n and d n .We know thatand alsoa =given these relationships we can now find[K = P c ρ −γca 2 4πGn+1 = Kρ1/n−1 cbut since we know that γ = 1/n+1 we findand finally we findP c ρ −γc ρ1/n−1 c(n+1)Kρc1/n−1 ] 1/24πG= P c ρ −γc ρc1/n−1= P c ρc−(1+1/n) ρc1/n−1 = P c ρ −2cusing this results we can now deriveP c = a2 4πGρ 2 cn+1which becomesP c = a2 4πGρ 2 cn+1P c = a2 4πGa 2 nn+1looking at these two expressions we can see that= GM2R 4 c n( ) 3M 24πR 3 = GM2R 4 c nc n = 9a2 a 2 n4πR 2 1n+1now looking atand from (b) we findP c = d n GM 2/3 ρ 4/3cP c = a2 4πGρc 2/3 ρc4/3 ( )= a2 4πG an 3M 2/3n+1 n+1 4πR 3 ρc4/316