Theory of Metal Cutting

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EXAMPLES To find speed at t = 50 min. Substitute t = 50 min equation (3) we getV60= 75 m/min. Repeating the same procedure for material Bwe get n=0.33 ,C=631 and V60 = 173.53 m/min. Relative machinability = [V60 for test material/ V60 for standard material] × 100 = [173.53/75] × 100 = 231.37%
Page 1 and 2: Theory of MetalCuttingChapter 4© r
Page 3 and 4: Machining or MetalCutting Removing
Page 5 and 6: © rkm2003Metal Cutting: featuresCl
Page 7 and 8: Essentials of MetalCutting Operatio
Page 9 and 10: Typical Machine toolToolWorkpieceVi
Page 11 and 12: © rkm2003Classification ofMachine
Page 13 and 14: © rkm2003Cutting Toolssharp edge/s
Page 15 and 16: Metal Cutting ..© rkm2003BasicsFea
Page 17 and 18: © rkm2003Geometry of Single Point
Page 19 and 20: © rkm2003Types of ChipsBuilt-upChi
Page 21 and 22: Thermal Aspects inMachiningHeat gen
Page 23 and 24: Thermal Aspects in Machining..Distr
Page 25 and 26: © rkm2003Operating ConditionsCondi
Page 27 and 28: Tool Life ..Cutting Speed (v)tool l
Page 29 and 30: Tool Life..Typical n & C VALUESWork
Page 31 and 32: Machinability• Tool life• Cutti
Page 33 and 34: © rkm2003EXAMPLE 4.1While machinin
Page 35 and 36: EXAMPLE 4.1 ..Solution(b)Given: vT
Page 37 and 38: EXAMPLES Solution: Given data: v1 =
Page 39 and 40: EXAMPLES Example 4.4 In assessingma
Page 41: EXAMPLES Substituting we getlog 100

Theory of Metal Cutting

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