Numerical Solutions of Linear Systems of Equations
Numerical Solutions of Linear Systems of Equations
Numerical Solutions of Linear Systems of Equations
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EE 216 Class NotesEqn. (1) (Row 1) cannot be used to eliminate x from Eqns. (2) and (3) (Rows 2 and 3).Interchange Row 1 with Row 2.The augmented matrix becomes:⎛40⎜⎜⎜⎝3234− 321− 10⎞169⎟⎟⎟⎠Now follow the steps mentioned earlier to solve for the unknowns.The solution is:x = - 3y = 4z = 2Let us consider the following set <strong>of</strong> linear equations.2x 1 – 4x 2 + 5x 3 = 36 … … (1)- 3x 1 + 5x 2 + 7x 3 = 7 … … (2)5x 1 + 3x 2 – 8x 3 = - 31 … … (3)Gauss elimination suggests doing elementary row operations from top to bottom. Aslightly modified form, known as Gauss-Jordan elimination suggests doing elementaryrow operations from bottom to top as well.Pages 7 <strong>of</strong> 21