Solutions Communications technology II WS 2009/2010 - Universität ...
Solutions Communications technology II WS 2009/2010 - Universität ...
Solutions Communications technology II WS 2009/2010 - Universität ...
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“<strong>Communications</strong> <strong>technology</strong> <strong>II</strong>” – <strong>Solutions</strong> <strong>WS</strong> <strong>2009</strong>/<strong>2010</strong> 82 ViterbiSolution to exercise 6 (vit01):(a), (b) S0 = {−1 − j}, S1 = {−1 + j}, S2 = {+1 − j}, S3 = {+1 + j}S0S1S3S4d(1)=1+jd(2)=1-jd(3)=-1-jd(4)=-1+jd(5)=-1-jz 0,0 = −2 − 2jz 0,1 = −2z 0,2 = −2jz 0,3 = 0z 1,0 = −2z 1,1 = −2 + 2jz 1,2 = 0z 1,3 = 2jz 2,0 = −2jz 2,1 = 0z 2,2 = 2 − 2jz 2,3 = 2z 3,0 = 0z 3,1 = 2jz 3,2 = 2z 3,3 = 2 + 2jc)λ 1 = |˜z 0,3 − (1.5 + j)| 2 = | + 1 + j − (1.5 + j)| 2 = 0.25λ 2 = |z 3,2 − (2 + 0.5j)| 2 = |2 − (2 + 0.5j)| 2 = 0.25λ 3 = |z 2,0 − (−3j)| 2 = | − 2j − (−3j)| 2 = 1λ 4 = |z 0,1 − (−2)| 2 = | − 2 − (−2)| 2 = 0λ 5 = |z 1,0 − (−2 + j)| 2 = | − 2 − (−2 + j)| 2 = 15∑λ i = 2.5i=1
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