Solutions Communications technology II WS 2009/2010 - Universität ...
Solutions Communications technology II WS 2009/2010 - Universität ...
Solutions Communications technology II WS 2009/2010 - Universität ...
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11 <strong>WS</strong> <strong>2009</strong>/<strong>2010</strong> “<strong>Communications</strong> <strong>technology</strong> <strong>II</strong>” – <strong>Solutions</strong>Solution to exercise 8 (vit10):(a) channel length=4 ; channel order=3;S 0 = {−1, −1, −1}S 1 = {−1, −1, +1}S 2 = {−1, +1, −1}S 3 = {−1, +1, +1}S 4 = {+1, −1, −1}S 5 = {+1, −1, +1}S 6 = {+1, +1, −1}S 7 = {+1, +1, +1}(b) d(i) = {+1, −1, +1, −1, +1, +1, −1, +1, −1, −1, −1}(c) f(i) = {+1, −1, −1, −1, −1, +1, −1, +1, −1, −1, −1}error vector: e(i) = (d(i) − f(i))/2⇒ e = [1 , 0, 1] T⇒ γ 2 min = eH F H Fe = 0.6
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