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A cryptographic solution for general access control - University of ...

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A Cryptographic Solution <strong>for</strong> General Access Control 467x ′ mod n si1 =(m e mod n si1 n si2 ...n sik )modn si1=(m e − qn si1 n si2 ...n sik )modn si1= m e mod n si1= E Ksi1 (m) .where m e = qn si1 n si2 ...n sik +r <strong>for</strong> some integers q and r (r

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