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The Nanocell: A Chemically Assembled Molecular ... - IEEE Xplore

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1618 <strong>IEEE</strong> SENSORS JOURNAL, VOL. 6, NO. 6, DECEMBER 2006Fig. 3. (a)–(c) Implementation of a logical AND using a tri-flourobenzene molecule using positive logic. <strong>The</strong> negative regions (red) correspond to a logical“zero” and the positive regions (blue) to a logical “one” at the output, indicated by the arrow at the right of the isolated hydrogen atom. <strong>The</strong> inputs are providedfrom the positive (white for the hydrogen) or negative (red for the oxygen) sides of the water molecule, and the output is taken on the right side of the isolatedhydrogen atom (white). <strong>The</strong> 00, 10, 11 inputs to the gate are shown, respectively. (d) Case for the 00 inputs, indicating the range of voltages (color coded)by the bar at the bottom. <strong>The</strong> other two cases have similar range of voltages. Notice that the potential at the nuclei is extremely large (and positive); however,those regions are not accessible by molecule–molecule interactions and are also chemically irrelevant. Carbon atoms are in green, fluorine in grey, and hydrogenin white.are used only as the sources applied to the inputs; they arenot part of the molecular gate. Simply, thanks to the dipolarnature of water, we can use the oxygen (negative) side as a“zero” input and the hydrogen side (positive) as a “one” inputto the molecular gate. We could use any other source that yieldspositive and negative potentials. In this case, we decided to usea molecular source for the sake of compatibility. Thus, Fig. 3(a)shows the 00 inputs yielding zero at the output; Fig. 3(b) showsthe 01 inputs, which is equivalent by symmetry to the 10,yielding zero; and Fig. 3(c) shows the 11 inputs yielding one.<strong>The</strong>se tests prove unambiguously that the molecule performs asa logical AND. It responds to the following truth table:V 1 V 2 V 00 0 00 1 01 0 01 1 1Interestingly, the energy needed to excite the molecule withthe two inputs is less than 0.5 eV [17]. This implies that it may.be possible to operate 200 million of these gates at 10-GHzfrequency with less than 1 W. More precisely(2 × 10 8 gates)(10 10 operation/s)(0.5 eV/gate-operation)×(1.6 × 10 9 J/eV) =0.16 J/s =0.16 W.This is certainly a rough estimate, most likely within the sameorder of magnitude of the exact value. This estimation considersthe energy to change states of the gate and excite their inputs.As gates are directly interconnected, losses in interconnectionsare perhaps a small fraction of the energy to change states.Nevertheless, even an error of one or two orders of magnitude,underestimating the power consumption, still represents anexcellent result. Using a similar logic to calculate the powerneeded in the modern Pentium XE and assuming a gate capacitanceof 40 aF, it amazingly yields 125 W (most likely a luckymatch), to which we need to consider the energy dissipation inthe interconnects, the energy needed to change the input states,and the utilization factor among others; all these should accountfor the total 130-W dissipation in the microprocessor.When comparing molecular devices to their microelectroniccounterparts, the question of gain is always a concern. However,

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