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Potential flow:

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2 CHAPTER 1. POTENTIAL FLOW:in which the vorticity is zero. Consider the cross product of the velocity andvorticity, u × ω = u × ∇ × u, which can be written in indicial notation as,ɛ ijk u j ɛ klm∂u m∂x l= (δ il δ jm − δ im δ jl )u j∂u m∂x l∂u i ∂u i= u j − u i∂x j ∂x j∂u i= u j − 1 ∂(u 2 i )(1.5)∂x j 2 ∂x jFor an irrotational <strong>flow</strong>, the left side of the above equation is zero since thevorticity ∇ × u is zero. Therefore,∂u iu j = 1 ∂(u 2 i )(1.6)∂x j 2 ∂x jUsing the above substitution for the second term on the left side of equation 1.4,and also expressing the first term on the left in terms of the velocity potentialusing equation 1.2, we obtain,∂ ∂φ+ 1 ∂t ∂x i 2∂(u 2 i )∂x i+ 1 ∂p− f iρ ∂x i ρ = 0 (1.7)If the body force f i is conservative, it can be expressed as the gradient of apotential V as follows,f i = − ∂V∂x i(1.8)When this is inserted into equation 1.7, and simplified, we obtain,(∂ ∂φ∂x i ∂t + 1 2 u2 i + p ρ + V )= 0 (1.9)ρSince all components of the gradient of the term in brackets is zero in the aboveequation, the term in brackets has to be equal to a constant,( ∂φ∂t + 1 2 u2 i + p ρ + V )= p 0(1.10)ρ ρwhere the constant p 0 is the reference pressure at a location where the velocityand potential V are zero. In a gravitational field, the potential is equal to ρgz,where z is the height above the zero-potential reference. Equation 1.10 can thenbe written as, ( ∂φ∂t + 1 2 u2 i + p )ρ + gz = p 0(1.11)ρEquation 1.11 is referred to as the ‘Bernoulli’ equation for the potential <strong>flow</strong>.An important point to note is that in potential <strong>flow</strong>s, it is possible to satisfyonly the normal velocity and stress conditions at a surface, and it is not possible

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