1.1 Integers and Rational Numbers

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$Lesson 2a – Assessment - Scottsdale Community College - Math Blog$

www.ck12.org Chapter 10. Linear FunctionsWe also saw another way to graph this equation. Just by looking at the equation, we could see that the y−interceptwas (0, 5), so we could start by plotting that point. Then we could also see that the slope was 2, so we could findanother point on the graph by going over 1 unit and up 2 units. The graph would then be the line between those twopoints.Heres another problem where we can use the same method.Example 3Graph the following function: y = −3x + 5SolutionTo graph the function without making a table, follow these steps:1. Identify the y−intercept: b = 52. Plot the intercept: (0, 5)3. Identify the slope: m = −3. (This is equal to −31, so the rise is -3 and the run is 1.)4. Move over 1 unit and down 3 units to find another point on the line: (1, 2)5. Draw the line through the points (0, 5) and (1, 2).195
10.2. Graphs Using Slope-Intercept Form www.ck12.orgNotice that to graph this equation based on its slope, we had to find the rise and runand it was easiest to do that whenthe slope was expressed as a fraction. Thats true in general: to graph a line with a particular slope, its easiest to firstexpress the slope as a fraction in simplest form, and then read off the numerator and the denominator of the fractionto get the rise and run of the graph.Example 4Find integer values for the rise and run of the following slopes, then graph lines with corresponding slopes.a) m = 3b) m = −2c) m = 0.75d) m = −0.375Solutiona)b)196
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1.1 Integers and Rational Numbers

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