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Functions and Inverses What's the use? If f exists, we could use it to ...

Functions and Inverses What's the use? If f exists, we could use it to ...

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<strong>Functions</strong> <strong>and</strong> <strong>Inverses</strong>Defin<strong>it</strong>ion: A function g is said <strong>to</strong> be <strong>the</strong> inverse of f if:1. domain of f = range of g,2. range of f = domain of g, <strong>and</strong>3. y = f(x) if <strong>and</strong> only if g(y) = x.Notation: f ­1 is <strong>the</strong> inverse of f.<strong>What's</strong> <strong>the</strong> <strong>use</strong>? <strong>If</strong> f ­1 <strong>exists</strong>, <strong>we</strong> <strong>could</strong> <strong>use</strong> <strong>it</strong> <strong>to</strong> solveequations like f(x) = 0, beca<strong>use</strong> <strong>the</strong>n...Jan 28­1:47 PM<strong>Functions</strong> <strong>and</strong> <strong>Inverses</strong>Visual Calculus ­ <strong>Inverses</strong> of <strong>Functions</strong> (Overview)Visual Calculus ­ <strong>Inverses</strong> of <strong>Functions</strong> (Flash Tu<strong>to</strong>rial)Jan 28­2:01 PM1


Examples ­ Decide whe<strong>the</strong>r f is one­<strong>to</strong>­one.­ ei<strong>the</strong>r <strong>use</strong> horizontal line test­ or apply defin<strong>it</strong>ion­ be sure <strong>to</strong> specify <strong>the</strong> domain!Jan 28­4:37 PMGiven a graph of y = f(x), <strong>we</strong> can sketch <strong>the</strong> inverse:f ­1 (x) = (x 2 ­2)/5a) Sketch f ­1 (x).b) State <strong>the</strong> domain <strong>and</strong> range.c) Find a formula for f ­1 (x).Jan 28­4:59 PM2


Find <strong>the</strong> inverse, f ­1 (x).Jan 28­4:45 PMInverse Trig <strong>Functions</strong>Does f(x) = sin(x) have an inverse?Does cos(x)? Does tan(x)?Jan 29­1:02 PM3


Important Calc II Skill:(<strong>use</strong>d w/ integration method of trig. subst.)(a) Evaluate cos(sin ­1 (x))(b) Evaluate tan(cos ­1 (x))Jan 29­1:06 PMDerivatives of Inverse Trig <strong>Functions</strong>(relies on implic<strong>it</strong> differentiation)Formula: d/dx [sin ­1 (x)] = 1/sqrt[1­x 2 ]Proof:Caution: <strong>the</strong> derivative,not sin ­1 <strong>it</strong>self!Jan 29­1:22 PM4

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