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A GP-AHP method for solving group decision-making fuzzy AHP ...

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C.-S. Yu / Computers & Operations Research 29 (2002) 1969–2001 1995<br />

where log ae 21j − log 3+de 21j ¿ 0, ae 21j ;de 21j ¿ 0, <strong>for</strong> j =2; 3, and e =1; 2; 3;<br />

log ae 312 = − 0:066949999 (log ae 312) − 1:8455416666 de 312 +0:544072297; (6.17)<br />

where log ae 312 − log 3+de 312 ¿ 0, ae 312 ;de 312 ¿ 0, <strong>for</strong> e =1; 2;<br />

log a3 312 = − 0:096910023 (log a3 312) − 1:775652326 d3 312 +0:397939017; (6.18)<br />

where log a3 312 − log 2+d3 312 ¿ 0, a3 312 ;d3 312 ¿ 0;<br />

log ae 313 = − 0:066949999 (log ae 313) − 1:845541666 de 313 +0:544072297; (6.19)<br />

where log ae 313 − log 3+de 313 ¿ 0, ae 313 ;de 313 ¿ 0, <strong>for</strong> e =1; 2; 3;<br />

log ae 323 = − 0:17609013 (log ae 323) − 2 de 323 +0:176091259; (6.20)<br />

where log ae 323 − log 1+de 323 ¿ 0, ae 323 ;de 323 ¿ 0, <strong>for</strong> e =1; 2; 3;<br />

log ae 413 = − 0:096910023 (log ae 413) − 1:775652326 de 413 +0:397939017; (6.21)<br />

where log ae 413 − log 2+de 413 ¿ 0, ae 413 ;de 413 ¿ 0, <strong>for</strong> e =1; 2;<br />

log a3 413 = − 0:124940028 (log a3 413) − 2:289237416 d3 413 − 0:17608998; (6.22)<br />

where log a 3 413<br />

1 − log( 2 )+d3 413 ¿ 0, a3 413 ;d3 413 ¿ 0;<br />

log ae 423 = − 0:124940028 (log ae 423) − 2:289237416 de 423 − 0:17608998; (6.23)<br />

where log ae 423 − log 2+de 423 ¿ 0, ae 423 ;de 423 ¿ 0, <strong>for</strong> e =1; 2; 3.<br />

Step 2: In the <strong>for</strong>m of the proposed model 2, Example 4 can be <strong>for</strong>mulated as follows:<br />

⎧<br />

⎨ 4� 4� 3�<br />

Minimize<br />

(log vq − log vq<br />

⎩<br />

′ − log aeqq ′ +2 e qq ′)<br />

q=1 q ′ ¿q e=1<br />

+<br />

⎧<br />

⎨<br />

−<br />

⎩<br />

4�<br />

3�<br />

3�<br />

q=1 i=1 j¿i e=1<br />

4�<br />

4�<br />

3�<br />

q=1 q ′ ¿q e=1<br />

Subject to (6:1)–(6:23);<br />

3�<br />

(log vqi − log vqj − log ae qij +2 e ⎫<br />

⎬<br />

qij)<br />

⎭<br />

(log a e qq ′)+<br />

4�<br />

3�<br />

3�<br />

3�<br />

q=1 i=1 j¿i e=1<br />

(log ae ⎫<br />

⎬<br />

qij)<br />

⎭<br />

log vq − log vq ′ − log ae qq ′ + e qq ′ ¿ 0; log vqi − log vqj − log a e qij + e qij ¿ 0;<br />

vq;vqi;a e qq ′;ae qij; e qq ′; e qij;d e ij;d e qij ¿ 0;<br />

(q; q ′ ) ∈{(q; q ′ ) | 1 6 q¡q ′ 6 4}; (i; j) ∈{(i; j) | 1 6 i¡j6 3}:<br />

Step 3: Using Theorem 1 to obtain M 1 =2:25871, M 0 =0:9860733, and =47=(M 1 − M 0 )=<br />

37:71697:<br />

Step 4: After running on the LINDO or EXCEL, the acquired solution set is (log v1 =0:26061,<br />

log v2 =0:405622, log v3 =0, log v4 =0:21752, log v11 =0:175915, log v12 =0, log v13 =0:276157,

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