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Topics in Cohomology of Groups_Serge Lang.pdf

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The above argument may be expressed <strong>in</strong> the form <strong>of</strong> a useful<br />

general lemma.<br />

If, <strong>in</strong> a cube, all the ]aces are commutative except possibly one,<br />

and one <strong>of</strong> the arrows as above is surjective, then this face is<br />

also commutative.<br />

Next we have to show that ~1 commutes with 6, that is (~P0,cPl)<br />

is a 6-morphism. Let<br />

0 ~ A' --* A ~ A" ~ 0<br />

be an exact sequence <strong>in</strong> 9/. Then there exist morphisms<br />

v : A ~ MA, and w : A" ---* XA,<br />

mak<strong>in</strong>g the follow<strong>in</strong>g diagram commutative:<br />

0 ) A' ~ A , A" ) 0<br />

0 ) A' ' ]VIA, ) XA' ) 0<br />

because MA, is <strong>in</strong>jective. There results the follow<strong>in</strong>g commutative<br />

diagram:<br />

H~ '')<br />

,,<br />

Ho(XA ,) 9 H'(A')<br />

~o /~) ~ ~(A')<br />

FO(XA ,) 9 r I(A')<br />

6F

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