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Topics in Cohomology of Groups_Serge Lang.pdf

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36<br />

both sides <strong>of</strong> the hexagon, we f<strong>in</strong>d that the factor groups <strong>of</strong> the two<br />

vertical sides have the same order, that is<br />

(Asc : (a - e)A) = (A~_~ : SGA).<br />

That h2/l(A) = 1 now follows from the def<strong>in</strong>itions.<br />

F<strong>in</strong>ally we have a result concern<strong>in</strong>g the Herrbrand quotient for<br />

trivial action.<br />

Theorem 5.4. Let G be a f<strong>in</strong>ite cyclic group <strong>of</strong> prime order p.<br />

Let A E Mod(G). Let t(A) be the Herbrand quotient relative to<br />

the trivial action <strong>of</strong> G on the abelian group A, so that<br />

t(A) - (Ap 0)<br />

(A/pA'O)<br />

Suppose this quotient is def<strong>in</strong>ed. Then t(AG), t(Av), and h2/l(A)<br />

are def<strong>in</strong>ed, and one has<br />

h2/l(A) p-1 = t(AC)P/t(A) = t(AG)P/t(A).<br />

Pro<strong>of</strong>. We leave the pro<strong>of</strong> as an exercise (not completely trivial).

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