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under the following combinations of transformations and state the<br />

equivalent single transformation in each case:<br />

(a) DE(OPQ) (b) FC(OPQ)<br />

(c) DEC(OPQ) (d) DFE(OPQ)<br />

5. Draw triangle XYZ at X(1, 2), Y(1, 6), Z(3, 6).<br />

(a) Find the image of XYZ under each of the transformations BC and CB.<br />

(b) Describe fully the single transformation equivalent to BC.<br />

(c) Describe fully the transformation M such that MCB = BC.<br />

Matrices of successive transformations<br />

If each of the successive transformations has a transformation matrix, then a<br />

single matrix that represents all the transformations can be obtained. Such a<br />

matrix maps the original object onto the final image.<br />

Example<br />

M and N are transformations represented by matrices M =<br />

1<br />

<br />

1<br />

2<br />

and<br />

3<br />

1<br />

0<br />

N = . P is a point with coordinates (-1, 2).<br />

2<br />

1<br />

(a) Find:<br />

(i) M(P) (ii) N(P)<br />

(iii) MN(P).<br />

(b) If R is a transformation such that R = MN, find R(P). What can you deduce<br />

from the results of (a) and (b)?<br />

Solutions<br />

1<br />

2<br />

1<br />

3 <br />

(a) (i) M(P) is = .<br />

1<br />

3<br />

2 5<br />

P1(3, 5)<br />

1<br />

0<br />

1<br />

1<br />

<br />

(ii) N(P) is = <br />

2<br />

1 2 0 <br />

P2(-1, 0)<br />

1<br />

1<br />

2<br />

1<br />

<br />

(iii) MN(P) = M[N(P)] = M<br />

= <br />

0 1<br />

3<br />

0 <br />

1 <br />

= <br />

1<br />

<br />

1<br />

2<br />

1<br />

0<br />

5<br />

2<br />

(b) R = MN= = <br />

1<br />

3<br />

2<br />

1<br />

7<br />

3<br />

5<br />

2<br />

1 1<br />

R(P) = = <br />

7<br />

3<br />

2 1

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