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Algebra 45<br />

10. p 2 − 3pq × 2p ÷ 6q + pq<br />

11. (x + 1)(x − 4) ÷ (2x + 2)<br />

12.<br />

1<br />

of 2y + 3y(2y − y)<br />

4<br />

6.5 Direct and inverse proportionality<br />

An expression such as y = 3x contains two variables. For every<br />

value of x there is a corresponding value of y. The variable x is<br />

called the independent variable and y is called the dependent<br />

variable.<br />

When an increase or decrease in an independent variable leads<br />

to an increase or decrease of the same proportion in the dependent<br />

variable this is termed direct proportion. Ify = 3x then y is<br />

directly proportional to x, which may be written as y ∝ x or y = kx,<br />

where k is called the coefficient of proportionality (in this case,<br />

k being equal to 3).<br />

When an increase in an independent variable leads to a<br />

decrease of the same proportion in the dependent variable (or<br />

vice versa) this is termed inverse proportion. Ify is inversely<br />

proportional to x then y ∝ 1 or y = k/x. Alternatively, k = xy,<br />

x<br />

that is, for inverse proportionality the product of the variables is<br />

constant.<br />

Examples of laws involving direct and inverse proportional in<br />

science include:<br />

(i) Hooke’s law, which states that within the elastic limit of<br />

a material, the strain ɛ produced is directly proportional to<br />

the stress, σ , producing it, i.e. ε ∝ σ or ε = kσ .<br />

(ii) Charles’s law, which states that for a given mass of gas at<br />

constant pressure the volume V is directly proportional to<br />

its thermodynamic temperature T, i.e. V ∝ T or V = kT.<br />

(iii) Ohm’s law, which states that the current I flowing through<br />

a fixed resistor is directly proportional to the applied voltage<br />

V , i.e. I ∝ V or I = kV .<br />

(iv) Boyle’s law, which states that for a gas at constant temperature,<br />

the volume V of a fixed mass of gas is inversely<br />

proportional to its absolute pressure p, i.e. p ∝ (1/V )or<br />

p = k/V , i.e. pV = k<br />

Problem 50. If y is directly proportional to x and y = 2.48<br />

when x = 0.4, determine (a) the coefficient of proportionality<br />

and (b) the value of y when x = 0.65<br />

(a) y ∝ x, i.e. y = kx. Ify = 2.48 when x = 0.4, 2.48 = k(0.4)<br />

Hence the coefficient of proportionality,<br />

k = 2.48<br />

0.4 = 6.2<br />

(b) y = kx, hence, when x = 0.65, y = (6.2)(0.65) = 4.03<br />

Problem 51. Hooke’s law states that stress σ is directly<br />

proportional to strain ε within the elastic limit of a<br />

material.When, for mild steel, the stress is 25 × 10 6 pascals,<br />

the strain is 0.000125. Determine (a) the coefficient of proportionality<br />

and (b) the value of strain when the stress is<br />

18 × 10 6 pascals.<br />

(a) σ ∝ ε, i.e. σ = kε, from which k = σ/ε. Hence the<br />

coefficient of proportionality,<br />

k =<br />

25 × 106<br />

0.000125 = 200 × 109 pascals<br />

(The coefficient of proportionality k in this case is called<br />

Young’s Modulus of Elasticity)<br />

(b) Since σ = kε, ε = σ/k<br />

Hence when σ = 18 × 10 6 , strain<br />

ε =<br />

18 × 106<br />

200 × 10 9 = 0.00009<br />

Problem 52. The electrical resistance R of a piece of wire<br />

is inversely proportional to the cross-sectional area A. When<br />

A = 5mm 2 , R = 7.02 ohms. Determine (a) the coefficient<br />

of proportionality and (b) the cross-sectional area when the<br />

resistance is 4 ohms.<br />

(a) R ∝ 1 , i.e. R = k/A or k = RA. Hence, when R = 7.2 and<br />

A<br />

A = 5, the coefficient of proportionality, k = (7.2)(5) = 36<br />

(b) Since k = RA then A = k/R<br />

When R = 4, the cross sectional area, A = 36<br />

4 = 9mm2<br />

Problem 53. Boyle’s law states that at constant temperature,<br />

the volume V of a fixed mass of gas is inversely<br />

proportional to its absolute pressure p. If a gas occupies<br />

a volume of 0.08 m 3 at a pressure of 1.5 × 10 6 pascals<br />

determine (a) the coefficient of proportionality and (b) the<br />

volume if the pressure is changed to 4 × 10 6 pascals..<br />

(a) V ∝ 1 , i.e. V = k/p or k = pV<br />

p<br />

Hence the coefficient of proportionality,<br />

(b) Volume V = k p<br />

k = (1.5 × 10 6 )(0.08) = 0.12 × 10 6<br />

=<br />

0.12 × 106<br />

4 × 10 6 = 0.03 m 3

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