Yet Another Calculus Text, 2007a
Yet Another Calculus Text, 2007a
Yet Another Calculus Text, 2007a
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30 CHAPTER 1. DERIVATIVES<br />
Exercise 1.7.5. Find the derivative of y =13x 5 .<br />
Example 1.7.7. Combining the power rule with our results for constant multiples<br />
and differences, we have<br />
d<br />
dx (3x2 − 5x) =6x − 5.<br />
Exercise 1.7.6. Find the derivative of f(x) =5x 4 − 3x 2 .<br />
Exercise 1.7.7. Find the derivative of y =3x 7 − 3x +1.<br />
1.7.4 Polynomials<br />
As the previous examples illustrate, we may put together the above results to<br />
easily differentiate any polynomial function. That is, if n ≥ 1anda n , a n−1 ,<br />
..., a 0 are any real constants, then<br />
d<br />
dx (a nx n + a n−1 x n−1 + ···+ a 2 x 2 + a 1 x + a 0 )<br />
= na n x n−1 +(n − 1)a n−1 x n−2 + ···+2a 2 x + a 1 . (1.7.26)<br />
Example 1.7.8. If p(x) =4x 7 − 13x 3 − x 2 + 21, then<br />
p ′ (x) =28x 6 − 39x 2 − 2x.<br />
Exercise 1.7.8. Find the derivative of f(x) =3x 5 − 6x 4 − 5x 2 + 13.<br />
1.7.5 Quotients<br />
If u is a differentiable function of x, u(x) ≠0,anddx is an infinitesimal, then<br />
( 1 1<br />
d =<br />
u)<br />
u(x + dx) − 1<br />
u(x)<br />
1<br />
=<br />
u(x)+du − 1<br />
u(x)<br />
u − (u + du)<br />
=<br />
u(u + du)<br />
−du<br />
=<br />
u(u + du) . (1.7.27)<br />
Hence, since u + du ≃ u, ifdx ≠0,<br />
( ) du<br />
d 1<br />
= − dx<br />
dx u u(u + du) ≃−1 du<br />
u 2 dx . (1.7.28)