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Yet Another Calculus Text, 2007a

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36 CHAPTER 1. DERIVATIVES<br />

Hence<br />

from which if follows that<br />

n−1 dy<br />

ny =1, (1.7.46)<br />

dx<br />

dy<br />

dx = 1<br />

ny n−1 = 1 n y1−n = 1 ( ) 1−n<br />

x 1 1<br />

n =<br />

n<br />

n x 1 n −1 , (1.7.47)<br />

showing that the power rule works for rational powers of the form 1 n<br />

. Note that<br />

the above derivation is not complete since we began with the assumption that<br />

y = x 1 n is differentiable. Although it is beyond the scope of this text, it may be<br />

shown that this assumption is justified for x>0ifn is even, and for all x ≠0<br />

if n is odd.<br />

Now if m ≠ 0 is also an integer, we have, using the chain rule as above,<br />

d<br />

dx x m n<br />

d<br />

(<br />

=<br />

dx<br />

= m<br />

) m<br />

x 1 n<br />

(<br />

x 1 n<br />

) m−1 1<br />

n x 1 n −1<br />

= m n x m−1<br />

n + 1 n −1<br />

= m n x m n −1 . (1.7.48)<br />

Hence we now see that the power rule holds for any non-zero rational exponent.<br />

Theorem 1.7.10. If r ≠ 0 is any rational number, then<br />

d<br />

dx xr = rx r−1 . (1.7.49)<br />

Example 1.7.18. With r = 1 2<br />

in the previous theorem, we have<br />

d √ 1 x =<br />

dx 2 x− 1 1<br />

2 =<br />

2 √ x ,<br />

in agreement with our earlier direct computation.<br />

Example 1.7.19. If y = x 2 3 ,then<br />

dy<br />

dx = 2 3 x− 1 2<br />

3 = .<br />

3x 1 3<br />

Note that dy<br />

dx<br />

is not defined at x = 0, in agreement with our earlier result showing<br />

that y is not differentiable at 0.<br />

Exercise 1.7.16. Find the derivative of f(x) =5x 4 5 .<br />

We may now generalize 1.7.44 as follows: If u is a differentiable function of<br />

x and r ≠ 0 is a rational number, then<br />

d<br />

dx ur = ru<br />

r−1 du<br />

dx . (1.7.50)

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