Yet Another Calculus Text, 2007a
Yet Another Calculus Text, 2007a
Yet Another Calculus Text, 2007a
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32 CHAPTER 1. DERIVATIVES<br />
Thus, for any nonzero infinitesimal dx,<br />
dy v du<br />
dx = dx − u dv<br />
dx ≃<br />
v(v + dv)<br />
This is the quotient rule.<br />
Theorem 1.7.8. If f and g are differentiable, g(x) ≠0,and<br />
v du<br />
dx − u dv<br />
dx<br />
v 2 . (1.7.35)<br />
q(x) = f(x)<br />
g(x) , (1.7.36)<br />
then<br />
q ′ (x) = g(x)f ′ (x) − f(x)g ′ (x)<br />
(g(x)) 2 . (1.7.37)<br />
Oneconsequenceofthequotientruleisthat,sincewealreadyknowhowto<br />
differentiate polynomials, we may now differentiate any rational function easily.<br />
Example 1.7.11. If<br />
then<br />
f(x) = 3x2 − 6x +4<br />
x 2 ,<br />
+1<br />
f ′ (x) = (x2 + 1)(6x − 6) − (3x 2 − 6x + 4)(2x)<br />
(x 2 +1) 2<br />
= 6x3 − 6x 2 +6x − 6 − 6x 3 +12x 2 − 8x<br />
(x 2 +1) 2<br />
= 6x2 − 2x − 6<br />
(x 2 +1) 2 .<br />
Example 1.7.12. We may use either 1.7.30 or 1.7.37 to differentiate<br />
y = 5<br />
x 2 +1 . (1.7.38)<br />
In either case, we obtain<br />
dy<br />
dx = − 5 d<br />
(x 2 +1) 2 dx (x2 +1)=−<br />
10x<br />
(x 2 +1) 2 . (1.7.39)<br />
Exercise 1.7.9.<br />
Exercise 1.7.10.<br />
Find the derivative of<br />
y =<br />
Find the derivative of<br />
14<br />
4x 3 − 3x .<br />
f(x) = 4x3 − 1<br />
x 2 − 5 .