05.01.2013 Views

An Analytic Algorithm for Generalized Abel Integral Equation

An Analytic Algorithm for Generalized Abel Integral Equation

An Analytic Algorithm for Generalized Abel Integral Equation

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

230 S. Kumar, O. P. Singh and S. Dixit<br />

L ( x ) =<br />

2<br />

9<br />

10<br />

x<br />

5<br />

3<br />

−<br />

27<br />

40<br />

x<br />

8<br />

3<br />

+<br />

x<br />

⎛ ⎛ 2<br />

⎜ Γ ⎜<br />

⎝ ⎝ 3<br />

⎛ 10 ⎞<br />

Γ ⎜ ⎟<br />

⎝ 3 ⎠<br />

7<br />

3<br />

⎞ ⎞<br />

⎟ ⎟<br />

⎠ ⎠<br />

2<br />

10 ⎛ 2<br />

3 ⎛ ⎞ ⎞<br />

3 x ⎜ Γ ⎜ ⎟ ⎟<br />

⎝ ⎝ 3 ⎠<br />

−<br />

⎠<br />

⎛ 10 ⎞<br />

5 Γ ⎜ ⎟<br />

⎝ 3 ⎠<br />

The Fig. (2) is drawn at the same level of truncation, n (=13) as was the case of Figure<br />

(1).<br />

2.5 10� 6<br />

2. 10� 6<br />

1.5 10� 6<br />

1. 10� 6<br />

5. 10� 7<br />

0.2 0.4 0.6 0.8 1.0<br />

Figure 2. The absolute error <strong>for</strong> Example 1, case 1(b) (n=13).<br />

From Figs.1 and 2, one observes the dependence of the convergence rate of the series<br />

(13) on the initial choice ( x).<br />

y o<br />

Case 1(c) Modified Homotopy perturbation method<br />

Writing ( ) ∑ ( ) .<br />

0<br />

∞<br />

2<br />

f x = k i x where k 0 ( x ) = x , k 1 ( x ) =<br />

i =<br />

27<br />

40<br />

8<br />

3 x and k i ( x)<br />

= 0 <strong>for</strong><br />

i ≥ 2,<br />

we get L<br />

2<br />

( x ) = x .<br />

0<br />

Hence, the various iterates are as follows:<br />

0<br />

p : L ( x ) = x<br />

p<br />

p<br />

1<br />

2<br />

:<br />

:<br />

0<br />

L ( x)<br />

=<br />

1<br />

L<br />

2<br />

27<br />

40<br />

x<br />

( x ) =<br />

2<br />

,<br />

8<br />

3<br />

x<br />

∫<br />

0<br />

−<br />

x<br />

∫<br />

0<br />

L<br />

L ( t)<br />

0<br />

( x − t)<br />

1<br />

( t )<br />

( x − t )<br />

1<br />

3<br />

There<strong>for</strong>e, one can see that Ln ( x)<br />

= 0,<br />

<strong>for</strong> all n ≥ 1,<br />

and hence,<br />

1<br />

3<br />

dt<br />

dt<br />

=<br />

=<br />

0,<br />

0 .<br />

2<br />

,...

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!