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Divisibilidad - Cepasanfrancisco.edurioja.org

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1Soluciones a los ejercicios y problemas<br />

48 Observa…<br />

(–2) 3 = (–2) · (–2) · (–2) = –8 (+2) 3 = (+2) · (+2) · (+2) = +8<br />

–23 = –2 · 2 · 2 = –8 +23 …y calcula.<br />

= +2 · 2 · 2 = +8<br />

a) (–3) 4 b)(+3) 4 c) –34 d)+34 a) 81 b) 81 c) –81 d) 81<br />

49 Expresa como potencia de un único número.<br />

a) 104 :54 b)127 :(–4) 7 c) (–9) 6 :36 d)26 · 26 e) (–4) 5 · (–2) 5 f)24 · (–5) 4<br />

a) 104 :54 = (2 · 5) 4 : 54 = (24 · 54 ) : 54 = 24 b) 127 :(–4) 7 = (3 · 4) 7 :(–4) 7 = (37 · 47 ) : (–4) 7 = –37 c) (–9) 6 :36 = 312 : 36 = 36 d) 26 · 26 = 212 e) (–4) 5 · (–2) 5 = –(45 ) · (–25 ) = 45 · 25 = 210 · 25 = 215 f) 24 · (–5) 4 = 24 · 54 = (2 · 5) 4 = 104 50 Reduce a una sola potencia.<br />

a) x 4 · x 6 b)m 3 · m 4<br />

c) m 8 : m 6 d)x 7 : x 6<br />

e) (x 2 ) 5 f)(m 4 ) 3<br />

g) [a 10 : a 6 ] 2 h)(a · a 3 ) 3<br />

i) (x 5 : x 2 )· x 4 j) (x 6 · x 4 ):x 7<br />

a) x 4 · x 6 = x 10 b) m 3 · m 4 = m 7<br />

c) m 8 : m 6 = m 8 : m 6 = m 2 d) x 7 : x 6 = x<br />

e) (x 2 ) 5 = x 10 f) (m 4 ) 3 = m 12<br />

g) [a 10 : a 6 ] 2 = a 8 h) (a · a 3 ) 3 = a 12<br />

i) (x 5 : x 2 )· x 4 = x 7 j) (x 6 · x 4 ):x 7 = x 3<br />

51 Expresa como una potencia única.<br />

a) 43 ·4 b)52 · (–5) 3<br />

c) (–6) 8 :(–6) 5 d)78 : (–7)<br />

e) (52 · 54 ):53 f)[74 · (–7) 4 ] : (–7) 6<br />

g) (24 ) 3 :29 h)(–4) 7 :(42 ) 2<br />

i) [(–3) 4 ] 3 : [(–3) 3 ] 3 j) (52 ) 5 : [(–5) 3 ] 2<br />

a) 43 · 4 = 44 b) 52 · (–5) 3 = –55 c) (–6) 8 :(–6) 5 = –63 d) 78 : (–7) = –77 e) (52 · 54 ):53 = 53 f) [74 · (–7) 4 ] : (–7) 6 = 72 g) (24 ) 3 :29 = 23 h) (–4) 7 :(42 ) 2 = –43 i) [(–3) 4 ] 3 : [(–3) 3 ] 3 = –33 j) (52 ) 5 : [(–5) 3 ] 2 = 54 Unidad 1. <strong>Divisibilidad</strong> y números enteros<br />

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