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x2∫x1SZdxCEM 383 Equation Sheet, Final Exam - 2004dW = FdsdW = −PdVW = −nRTln( V 2 V1)1 cal = 4.184 J⎛ dQV⎞ ⎛ dE ⎞CV= ⎜ ⎟ = ⎜ ⎟ W = CV ( T 2 −T1)⎝ dT ⎠ ⎝ dT ⎠ VdQ = CdT⎛ dQP⎞ ⎛ dH ⎞CdE = dW + dQP = ⎜ ⎟ = ⎜ ⎟⎝ dT ⎠ ⎝ dT ⎠dZdS = Qrev / TdS = dS +==Z(x,=xtot2= ln Ωk B−xsysy,K)( dZ / dx)dSlimT →0K∆S = CV ln +∆Horxno∆S∆CP=1x2dx∫ = lnxx1surrS=P0( T T ) nR ( V V )2 1 ln∑( x x )212E = K.E.+ UdE = dQ dH =1y , K dx + ( dZ / dy)x,Kdy+n∆HoofV dQ PdE = dH − PdVdE = TdS − PdVdH = TdS + VdP( dT / dV ) = −(dP / dS)S( dT / dP)= ( dV / dS)SL(products) -∑ m∆H= ∑ nS(products) -∑= ∑ nC(products) -∑PmSomCofPV( reactants)( reactants)P( reactants)