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Mathematical Modelling

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Inleiding Complexe getallen; review Complexe functies<br />

Huiswerk<br />

Vind alle oplossingen van de vergelijking:<br />

(z + 1) 5 = z 5<br />

5.<br />

5√<br />

1 = e 2kπi/5 ,<br />

k = 0, 1, 2, 3, 4 en dus<br />

z + 1 = ze 2kπi/5 → z(1 − e 2kπi/5 ) = −1<br />

−1<br />

→ z =<br />

, k = 0, 1, 2, 3, 4<br />

1 − e2kπi/5

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