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θ 2 =0β = 0 3.6 θ c <br />
cos θ c = 1 − δ (3.7)<br />
δ ≪ 1 θ c ≪ 1 cos θ c ≅ 1 − 1 2 θ2 c 3.2<br />
3.7 θ c <br />
( ) 1<br />
θ c (deg.) ≅ (2δ) 1 2 = 1.33 × 10<br />
7 ρf1 2<br />
λ<br />
A<br />
(3.8)<br />
( ) 1<br />
ρf1 2 1<br />
= 1.65<br />
A E<br />
(3.9)<br />
E X keVλ cmρ g/cm 3 <br />
f 1 E ( E )[keV]=1.240 × 10 −7 /λ [cm] <br />
f 1 ∼Z Z<br />
A<br />
∼ 0.7 = <br />
3.8<br />
( 1 ) ( 1 )<br />
ρ 2 ρ 2<br />
θ c ∼ 1.4 × ∝<br />
(3.10)<br />
E E<br />
<br />
3.10 X <br />
X <br />
PtAu X <br />
Pt 30 keV<br />
X 3.10 0.19 ◦ <br />
3.1.2 <br />
ñ<br />
X θ 1 <br />
σ π r σ r π <br />
<br />
r σ = sin θ 1 − ñ sin θ 2<br />
sin θ 1 + ñ sin θ 2<br />
= sin(θ 1 − θ 2 )<br />
sin(θ 1 + θ 2 ) (3.11)<br />
r π = sin θ 2 − ñ sin θ 1<br />
= − tan(θ 1 − θ 2 )<br />
sin θ 2 + ñ sin θ 1 tan(θ 1 + θ 2 )<br />
(3.12)<br />
13 θ 2 (3.6) (3.11),(3.12) <br />
R σ ,R π <br />
R σ = r σ rσ ∗ ≅ h − (θ 1/θ c ) √ 2(h − 1)<br />
h + (θ 1 /θ c ) √ 2(h − 1) (3.13)<br />
R π = r π rπ ∗ = R σ × R π<br />
= R σ ×<br />
cos(θ 1 + θ 2 )<br />
2<br />
R ∣<br />
σ cos(θ 1 − θ 2 ) ∣<br />
(3.14)<br />
<br />
h =<br />
( ) 2 θ1 √ (θ1<br />
+<br />
√(<br />
θ c<br />
θ c<br />
) 2<br />
− 1<br />
) 2 ( ) k 2<br />
+<br />
(3.15)<br />
δ<br />
11