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d H φ H d L φ L m
θ m
|F (θ m )| = d
mπ sin(mπγ)(φ H − φ L ) (3.27)
φ |F (θ)|
m m
R m R I m R m = tanh 2 A (3.28)
A
R I m = A tan θ m
mN
tanh A (3.29)
A = 2KNd
m |F (θ m)| (3.30)
K σ K σ =1π K π =| cos 2θ m | d
A ≪ 1tanh A ≅ A (3.29) (3.28)
R m = tanh 2 A ≅ A 2 (3.31)
R I m = A tan θ m
mN
tanh A ≅ A2 tan θ m
mN
(3.32)
(3.30) A K
R m R I m K2 σ
R mσ π R mπ R I mσ
R I mπ
R mπ
R mσ
= RI mπ
R I mσ
=
( Kπ
K σ
) 2
= cos 2 2θ m (3.33)
(10keV ) θ m ≪ 1 (3.33)
R mπ
R mσ
= RI mπ
R I mσ
= cos 2 2θ m ≅ 1 − 4θ 2 m (3.34)
(3.18) θ 2 θ 1
X 10 keV θ m