CURSO de ENGENHARIA (MECÃNICA) â VOLTA REDONDA ... - Uff
CURSO de ENGENHARIA (MECÃNICA) â VOLTA REDONDA ... - Uff
CURSO de ENGENHARIA (MECÃNICA) â VOLTA REDONDA ... - Uff
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PROAC / COSEAC - GabaritoCálculos e respostas:No ponto C: P C V C = n RT C o que nos leva a T C = 2 P 0 V 0 / nR = T / 2No ponto D: P D V D = n RT D o que nos leva a T D = 8 P 0 V 0 / nR = 4 Tb)e = W / Q enportantoe =| Q en | - | Q sai | | Q sai |_______= 1 -Q em | Q en |__________________(9)Q en = Q BC + Q CD Q sai = Q AB + Q DAQ BC = nc V ∆T = nc V (T C -T B ) Q AB = nc P ∆T = nc P (T B -T A )= nc V T/4 = - nc P 3T/4Q CD = nc P ∆T = nc P (T D -T C ) Q DA = nc V ∆T = nc V (T A -T D )= nc P 5T/2 = - nc V 3T/4Q en = nc V T/4 + nc P 5T/2 |Q sai | = nc P 3T/4 + nc V 3T/4usando o fato <strong>de</strong> que (c P /c V )= γ po<strong>de</strong>mos escrever:Q en = n c V T ( 1 + 10γ ) / 4 |Q sai | = n c V T ( 12 + 3γ ) / 4 (10)Substituindo (10 ) em (9) temos:e = 1 - ( 12 + 3γ )/ ( 1 + 10γ )13
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