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ZADATAK 1 - FESB

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Elementi strojeva 2 (Auditorne vježbe šk.god. 2004/05) – ISPITNI <strong>ZADATAK</strong>50Promjer gonjene remenice:d2 = id1= 1,8 ⋅ 100 = 180 mmto je standardni promjer pa nije potrebna dodatna kontrola prijenosnog omjera (inače ∆ idop< 5% ).Osni razmak:( )( )a' = 0,7...2,1 d + d = d + d = 100 + 180 = 280 mm1 2 1 2βββα1α2ββDuljina remena (slika 12.1):Slika 12.1 Remenski prijenosgdje je:π L'= 2 a'cosβ+ ( d1+ d2) +β( d2 −d 1)(12.1)2d2 − d1 180 − 100β= arcsin = arcsin = 8,2132 a ' 2⋅280α1= 180 −2β= 180 −2 ⋅ 8,213 = 163,574Uvrštavanjem u izraz (12.1) dobiva se:ππL ' = 2 ⋅280 ⋅ cos8,213 + ( 100 + 180) + 8,213⋅ ( 180 − 100)= 1005,548 mm2 180ooKatedra za elemente strojeva – Srđan Podrug

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