Electromagnetic Waves

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E : Perpendicular to the plane of incidence • Since the E-fields are parallel to the surface the 1st BC of (38) yields nothing • The 3rd and 4th of of (38) give (how?): E0 + E ′′ 0 − E ′ 0 = 0 ɛ µ (E0 − E ′′ ɛ 0 ) cos i − ′ µ ′ E ′ 0 cos r = 0 (38) • The 2nd, using Snell’s law, duplicates the 3rd. (prove all the above statements) Figure: Reflection and refraction with polarization perpendicular to the plane of incidence. All the E-fields shown directed away from the viewer. Electromagnetic Waves
E : Perpendicular to the plane of incidence The relative amplitudes of the refracted and reflected waves can be found from (38) E ′ 0 2n cos i = E0 n cos i + µ µ ′ n ′2 − n2 sin 2 i = 2 µ tan i 1 + µ ′ 2 sin r cos i = sin(i + r) tan r µ=µ ′ E ′′ 0 = E0 n cos i − µ µ ′ n ′2 − n2 sin 2 i n cos i + µ µ ′ n ′2 − n2 sin 2 µ tan i 1 − µ = i ′ tan r µ tan i 1 + µ ′ sin(r − i) = sin(i + r) tan r µ=µ ′ (39) Note that n ′2 − n2 sin 2 i = n ′ cos r but Snell’s law has been used to express it in terms of the angle of incidence. For optical frequencies it is usually permitted to put µ = µ ′ . Electromagnetic Waves
Page 1 and 2: Electromagnetic Waves May 4, 2010 1
Page 3 and 4: Plane Electromagnetic Waves Maxwell
Page 5 and 6: It is then useful to introduce a se
Page 7 and 8: The time averaged flux of energy is
Page 9 and 10: LINEARLY POLARIZED If the amplitude
Page 11 and 12: Elliptically Polarized EM Waves An
Page 13 and 14: Polarization Figure: The figure sho
Page 15 and 16: In terms of the linear polarization
Page 17 and 18: Reflection & Refraction of EM Waves
Page 19 and 20: According to eqn (18) the 3 waves a
Page 21: Reflection & Refraction of EM Waves
Page 25 and 26: E : Parallel to the plane of incide

Electromagnetic Waves

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