Quick start gaucho knots with locked edges

Quick start gaucho knots
with locked edges
The 4 bight locked edge gaucho with 2 pass coding
All possible lengths (parts) of this family of knots will braid as a quick
start knot.
You only need to know two things to set them up on a 4 pin mandrel.
1- The top bight number for the first half cycle.
2- The number of wraps around the mandrel to reach that bight pin.
They both may be found with the expression 1/2 the parts ÷ bights (4) = n + r.
The quotient n is the number of wraps and the remainder r is the top bight
number.
These are the only things that change in this series of knots except the 4 part
increments in bights for each increment in length. The half cycle code
sequences are always a braid entry of O1 followed by a series of U2-O2 segments
ending with a braid exit of U1
⇐ A 7 part knot. The
minimum possible size
for these knots.
The first top bight is 3
÷ 4 = 0 + 3 for no full
wraps to bight 3. (we
drop the fractional part
of 1/2 7 (3.5 because of
the 1/2 bight vertical
bight offset of odd part knots).
Note the half cycle code sequences of O1-U2-O2-U1 as predicted.The U1 segments
in the even hc of cycle 3 and odd hc of cycle 4 are because we are crossing
interstices that will be filled by a later hc. The easiest way to handle these
is to count them in the sequence as U's and just use the generic hc sequences.
⇐ Now 11 parts.5 ÷
4 = 1 + 1 for one
wrap to bight 1 at
the top.Another set
of U2-O2's in the
half cycle
sequences.
Also notice that
after the first
cycle is in place
you are always "on
rails" parralel and adjacent to the preceeding string run. Thus you don't need
to be concerned about bight numbers from there on.
1

RED grid.
1 ↑bottom pin 0 to top pin 5
2 ↓top pin 5 O1 to bottom pin 4
3 ↑bottom pin 4 O1 to top pin 2
4 ↓top pin 2 O3 to bottom pin 1
5 ↑bottom pin 1 O3 to top pin 6
6 ↓top pin 6 O4 to bottom pin 5
7 ↑bottom pin 5 O4 to top pin 3
8 ↓top pin 3 O4 U1 O1 to bottom pin 2
⇐Two more increments in length with the top bight pin
and wraps for the first cycle calculated and
highlighted.
You may see a pattern here in that each 4 part
increment changes the top bight pin between pins 3 and
1. The first cycle always terminates at bight 3 at the
bottom bight boundary.
These can serve as a check of the process to catch any
error.
A word about the mandrel size.
The optimum circumference is (1.4 X the string width)
X the bights (4). This is just an approximation and
can vary as much as 50% if needed.
The minimum spacing between bight boundaries is (1.4 X
string width)X (parts ÷ 2).
Eleven parts
The rest of the knot (The white leads in the right grid)
9 ↑bottom pin 2 O4 U1 O1 to top pin 0
10 ↓top pin 0 O2 U1 O2 U1 O1 to bottom pin 6
11 ↑bottom pin 6 O2 U1 O2 U1 O1 to top pin 4
12 ↓top pin 4 U1 O2 U1 O2 U2 O1 to bottom pin 3
13 ↑bottom pin 3 U1 O2 U1 O2 U2 O1 to top pin 1
14 ↓top pin 1 U1 O2 U2 O2 U2 O1 to bottom pin 0
⇐11 parts X 7 bights.
The left grid is the first eight half
cycles on the mandrel. Notice that the
first Under Xing is at the end of the
eighth half cycle (the black arrow.)
A run list is below.(The first U Xing
is at the end of hc 8.)
2

11 X 15
The quickstart sequence.The free runs give us more than half the knot.
Again the rest of the knot in white.
↑ bottom pin 0 to top pin 5
↓ top pin 5 to bottom pin 11
↑ bottom pin 11 to top pin 1
↓ top pin 1 O1 to bottom pin 7
↑ bottom pin 7 O1 to top pin 12
↓ top pin 12 O2 to bottom pin 3
↑ bottom pin 3 O2 to top pin 8
↓ top pin 8 O2 to bottom pin 14
↑ bottom pin 14 O2 to top pin 4
↓ top pin 4 O3 to bottom pin 10
↑ bottom pin 10 O3 to top pin 0
↓ top pin 0 O4 to bottom pin 6
↑ bottom pin 6 O4 to top pin 11
↓ top pin 11 O5 to bottom pin 2
↑ bottom pin 2 O5 to top pin 7
↓ top pin 7 O5 to bottom pin 13
↑ bottom pin 13 O5 to top pin 3
↓ top pin 3 O1 U1 O4 to bottom pin 9
↑ bottom pin 9 O1 U1 O4 to top pin 14
↓ top pin 14 O1 U1 O2 U1 O2 to bottom pin
5
↑ bottom pin 5 O1 U1 O2 U1 O2 to top pin
10
↓ top pin 10 O1 U1 O2 U1 O2 U1 to bottom
pin 1
↑ bottom pin 1 O1 U1 O2 U1 O2 U1 to top
pin 6
↓ top pin 6 O1 U1 O2 U1 O2 U1 to bottom
pin 12
↑ bottom pin 12 O1 U1 O2 U1 O2 U1 to top
pin 2
↓ top pin 2 O1 U2 O2 U1 O2 U1 to bottom pin 8
↑ bottom pin 8 O1 U2 O2 U1 O2 U1 to top pin 13
↓ top pin 13 O1 U2 O2 U2 O2 U1 to bottom pin 4
↑ bottom pin 4 O1 U2 O2 U2 O2 U1 to top pin 9
↓ top pin 9 O1 U2 O2 U2 O2 U1 to bottom pin 0
3

The quickstart part
The rest of the knot. (In white.)
A variation
⇐ If you look at the second part of the
single string grid above you see the
begining of a symetric color pattern.
If you start a new string at pin seven with
a contrasting color and finish the knot as
a partial interweave it produces this color
pattern.(This is one half cycle past the
center of the knot)
This basic idea works with most of these
knots.
15 X 11
↑ bottom pin 0 to top pin 7
↓ top pin 7 O1 to bottom pin 4
↑ bottom pin 4 O1 to top pin 0
↓ top pin 0 O2 to bottom pin 8
↑ bottom pin 8 O2 to top pin 4
↓ top pin 4 O4 to bottom pin 1
↑ bottom pin 1 O4 to top pin 8
↓ top pin 8 O5 to bottom pin 5
↑ bottom pin 5 O5 to top pin 1
↓ top pin 1 O6 to bottom pin 9
↑ bottom pin 9 O6 to top pin 5
↓ top pin 5 O6 U1 O1 to bottom pin 2
↑ bottom pin 2 O6 U1 O1 to top pin 9
↓ top pin 9 O4 U1 O2 U1 O1 to bottom pin 6
↑ bottom pin 6 O4 U1 O2 U1 O1 to top pin 2
↓ top pin 2 O2 U1 O2 U1 O2 U1 O1 to bottom pin 10
↑ bottom pin 10 O2 U1 O2 U1 O2 U1 O1 to top pin 6
↓ top pin 6 U1 O2 U1 O2 U1 O2 U2 O1 to bottom pin 3
↑ bottom pin 3 U1 O2 U1 O2 U1 O2 U2 O1 to top pin 10
↓ top pin 10 U1 O2 U1 O2 U2 O2 U2 O1 to bottom pin 7
↑ bottom pin 7 U1 O2 U1 O2 U2 O2 U2 O1 to top pin 3
↓ top pin 3 U1 O2 U2 O2 U2 O2 U2 O1 to bottom pin 1
4