link to lecture transcript - UT-H GSBS Medical Physics Class Site

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More important is the energy distribution. We have incident photons interacting with absorbing material via Compton interactions. Let’s look at a monoenergetic beam of photons and determine the distribution of energies of the Compton electrons that are going to be produced. Let’s determine the probability distribution of electrons generated from a monoenergetic photon. 20
This probability is represented by dσ/dE. We can write this as the quantity dσ/dθ times dθ/dE. We have already calculated dσ/dθ, so all we need to calculate is dθ/dE. We have an equation of energy as a function of scatter angle, and we can use this equation to get dE/dθ. 21
Page 1 and 2: Today, we continue our talk about C
Page 3 and 4: We previously derived an equation f
Page 5 and 6: So σ 0 is the classical cross sect
Page 7 and 8: Let’s look at this graph. Notice
Page 9 and 10: What about the dependence of the Co
Page 11 and 12: The energy transferred to the elect
Page 13 and 14: If we plot the energy transfer coef
Page 15 and 16: The energy transfer coefficient has
Page 17 and 18: What about the scatter coefficient?
Page 19: Using this equation we can now plot
Page 23 and 24: This figure is a plot taken from Jo
Page 25 and 26: We can always calculate what the ma
Page 27 and 28: Remember dσ/dE is relatively const
Page 29 and 30: Now we also look at the graph and s
Page 31 and 32: First, let’s recall that the atte
Page 33 and 34: What we now want to find out is how
Page 35 and 36: So far, our approximations have bee
Page 37 and 38: These values were tabulated by Hubb
Page 39 and 40: So what is the effect of binding en
Page 41 and 42: At higher energies there is no diff
Page 43 and 44: Note that this graph is for very lo
Page 45: The fraction of energy transferred

link to lecture transcript - UT-H GSBS Medical Physics Class Site

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