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Section 2<br />

38 I Installation, maintenance & designer guide<br />

Designer Guide<br />

H- 90° sprocket lap<br />

683 x 1.025 700<br />

I - Horizontal section<br />

[(19.68 + 65.62) x 15 x 0.15] x 9.81<br />

= 1883N 2583<br />

J-180° sprocket lap<br />

2583 x 1.05 2712<br />

K- Horizontal section<br />

[(19.68 + 65.62) x 15 x 0.15] x 9.81<br />

= 1883N 4595<br />

L- 180° sprocket lap<br />

4595 x 1.05 4825<br />

M - Horizontal section<br />

[(19.68 + 65.62) x 10 x 0.15] x 9.81<br />

= 1255N 6080<br />

N- Bend section<br />

6080 x eµ cθ 6080 x 1.082 6579<br />

P- Inclined section<br />

[(Wc + Wm) x L x µ s2] x 9.81<br />

[(19.68 + 65.62) x 3 x 0.63] x 9.81<br />

= 1582N 8161<br />

Q- Bend section<br />

8161 x eµ cθ 8161 x 1.082 8830<br />

R- Horizontal section<br />

[(19.68 + 65.62) x 4 x 0.15] x 9.81<br />

= 502N 9332 (-665)<br />

. . . Total <strong>chain</strong> pull Cp = 9332 N<br />

*NOTE: The negative figure is ignored when<br />

establishing <strong>chain</strong> strength required.<br />

However, this figure is taken into<br />

account when calculating headshaft<br />

power or torque.<br />

Using a general safety factor of 8, then <strong>chain</strong><br />

breaking load required would be:<br />

9332 x 8 = 37328 (N) per <strong>chain</strong><br />

2<br />

As a hollow bearing pin <strong>chain</strong> will be required<br />

for fitting the staybars then 2 strands of 54 kN<br />

(12000 lbf) <strong>chain</strong> of 152.4 mm (6'' pitch) would<br />

be suitable. It would now be correct to<br />

recalculate the above using the actual mass of<br />

54 kN (12000 lbf) <strong>chain</strong> and µ c from the friction<br />

factors listed on page 75 table 2.<br />

From catalogue, Chain total mass Wc<br />

= 4.89 kg/m per <strong>chain</strong><br />

For two <strong>chain</strong>s<br />

= 9.78 kg/m total<br />

Total mass of <strong>chain</strong> + staybars<br />

= 9.78 + 9.84 = 19.62 kg/m<br />

Coefficient of friction µ c<br />

= 0.14 (occasional lubrication)<br />

By recalculating, the maximum <strong>chain</strong> pull<br />

would be 8805 (N) with negative value 665 (N).<br />

Safety Factor = 2 x 54000 = 12.3<br />

8805<br />

This is quite satisfactory.<br />

Due to the bend sections it is necessary to<br />

check the imposed roller load due to the bend<br />

and staybar loads.<br />

Load at staybar<br />

= [20 + 3 + (9.78 x 304.8)] x 9.81 (N)<br />

1000<br />

= 255 N<br />

Load per roller R<br />

= 255 = 127.5 N<br />

2<br />

Bearing area of roller<br />

= 420 mm2 (See page 76 table 3)<br />

Bearing pressure P<br />

= 127.5 = 0.3 N/mm2 420<br />

Imposed load due to bend<br />

= Pull at exit (N) x Pitch (m)<br />

Bend Rad (m)<br />

On recalculating, pull at exit of top bend (Q)<br />

= 8337 N<br />

. . . Imposed load<br />

= 8337 x 0.3048 = 1271 N<br />

2<br />

Imposed load per roller<br />

= 1271 = 636 N<br />

2<br />

. . . Total roller load R<br />

= 636 + 127.5 = 763.5 N<br />

Bearing pressure P<br />

= 763.5 = 1.82 N/mm2 420<br />

As this series of <strong>chain</strong> has a sintered steel roller,<br />

maximum allowable pressure P = 1.2 N/mm2 at<br />

0.5 m/sec.<br />

Our figure of 1.8 N/mm2 is above this figure but<br />

as the <strong>chain</strong> speed is only 0.067 m/sec, the P VR<br />

value for average conditions can be checked by<br />

the method shown on page 76-77.<br />

Rubbing speed VR<br />

= Chain speed (m/sec) x roller bore (mm)<br />

Roller dia (mm)<br />

= 0.067 x 23.6 = 0.033 m/sec<br />

47.6<br />

. . . PVR = Pressure x Rubbing Speed<br />

= 1.82 x 0.033 = 0.06<br />

Maximum P VR for average condition for a<br />

sintered steel roller is 0.30.<br />

. . . The standard roller is satisfactory.<br />

. . . Use 2 strands of 54 kN (12000 lbf) <strong>chain</strong>,<br />

154.2 mm pitch, <strong>chain</strong> no. 105241/16.<br />

Power required at headshaft<br />

= Cp x V kW<br />

1000<br />

= (8805 - 665) x 0.067<br />

1000<br />

= 0.55 kW<br />

PCD (12 tooth)<br />

= 588.82 mm . . . RPM<br />

= V (m/sec) x 60<br />

PCD (m) x π<br />

= 0.067 x 60<br />

0.58882 x π<br />

= 2.2 RPM<br />

Headshaft torque<br />

= (8805 - 665) x 0.5882 Nm<br />

2<br />

= 2394 Nm

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