04.04.2013 Views

Math 133 — Introduction to Series Worksheet

Math 133 — Introduction to Series Worksheet

Math 133 — Introduction to Series Worksheet

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

<strong>Math</strong> <strong>133</strong> <strong>—</strong> <strong>Introduction</strong> <strong>to</strong> <strong>Series</strong> <strong>Worksheet</strong><br />

Directions: Read, filling in the blanks as you go.<br />

A series is an sum of infinitely many numbers. For example,<br />

1<br />

2<br />

+ 1<br />

4<br />

+ 1<br />

8<br />

+ 1<br />

16<br />

+ 1<br />

32<br />

TH Parker, 2013<br />

+ ··· (1)<br />

where the dots indicate that we continue, summing infinitely many terms according <strong>to</strong> the pattern<br />

indicated (powers of 2 in the denomina<strong>to</strong>r). The <strong>to</strong>tal sum is calculated by adding up the<br />

first 10 terms, then the first 100, then the first 1000 (these are called the “partial sums”) and<br />

then taking a limit (this is made more precise below).<br />

Problem 1 Compute the partial sums of the series (1) above by filling in the blanks. Write<br />

your answers as fractions, not decimals.<br />

s1 = first term = s2 = sum of the first two terms =<br />

In general, we write sn = sum of the first n terms (the s stands for “sum”); this number sn is<br />

called the n th partial sum. Keep going, still writing as fractions:<br />

s3 = s6 =<br />

s4 = s7 =<br />

s5 = s8 =<br />

These partial sums seem <strong>to</strong> be approaching the number . In fact, we can write the n th<br />

partial sum as a fraction with denomina<strong>to</strong>r 2 n , namely<br />

and then take the limit:<br />

lim<br />

n→∞ sn = lim<br />

n→∞<br />

=<br />

sn =<br />

(fill in <strong>to</strong> take the limit; it helps <strong>to</strong> rewrite by dividing numera<strong>to</strong>r and denomina<strong>to</strong>r by 2 n ).<br />

Definition If the partial sums converge <strong>to</strong> a limit S we say the series converges and that its<br />

sum is S. If the parial sums do not have a finite limit we say the series diverges.


Problem 2 Consider the series<br />

2<br />

5<br />

+ 2<br />

25<br />

+ 2<br />

125<br />

+ 2<br />

625<br />

+ ··· (2)<br />

(the denomina<strong>to</strong>rs are powers of 5). Write the partial sums in the form 1<br />

−(something) and,<br />

2<br />

based on the pattern, guess a formula for sn:<br />

s1 = 2<br />

5<br />

= 1<br />

2 − 10<br />

s2 = 2 2<br />

+<br />

5 25 = 25<br />

s3 = 2<br />

5<br />

+ 2<br />

25<br />

Since lim<br />

n→∞ sn = lim<br />

n→∞<br />

Problem 3 For the series<br />

= 1<br />

2 − 50<br />

+ 2<br />

125 = 125<br />

= 1<br />

2 −<br />

s4 = = 1<br />

2 −<br />

sn =<br />

1<br />

− = , the series (2) converges and its sum is S = .<br />

2<br />

1<br />

17<br />

+ 1<br />

17<br />

+ 1<br />

17<br />

+ 1<br />

17<br />

+ 1<br />

17<br />

(all terms are the same) the n th partial sum is sn = . Because<br />

lim<br />

n→∞ sn = lim<br />

n→∞<br />

the series (3) converges/ diverges (circle one).<br />

+ ··· (3)<br />

= ,<br />

Problem 4 For each wholenumbernwecan findanothernumbern!(pronounced“nfac<strong>to</strong>rial”)<br />

by multiplying <strong>to</strong>gether all the whole numbers up <strong>to</strong> n:<br />

Using a calcula<strong>to</strong>r, find these fac<strong>to</strong>rials:<br />

n! = 1·2·3·4···n<br />

2! = 1·2 = 5! = 8! =<br />

3! = 1·2·3 = 6! = 9! =<br />

4! = 1·2·3·4 = 7! = 10! =


Problem 5 Now consider the series<br />

1 + 1 + 1<br />

2!<br />

+ 1<br />

3!<br />

+ 1<br />

4!<br />

+ 1<br />

5!<br />

+ 1<br />

6!<br />

+ ··· (4)<br />

Using a calcula<strong>to</strong>r, write down the partial sums as decimals (record 6 digits after the decimal<br />

point):<br />

s3 = s6 = s9 =<br />

s4 = s7 = s10 =<br />

s5 = s8 = s11 =<br />

The series (4) seems <strong>to</strong> converge and the sum appears <strong>to</strong> be the number S =<br />

(the number s11 is very close <strong>to</strong> what famous number?).<br />

Problem 6 Now modify the series in the previous problem by making the signs alternate:<br />

1 − 1 + 1<br />

2!<br />

− 1<br />

3!<br />

+ 1<br />

4!<br />

− 1<br />

5!<br />

+ 1<br />

6!<br />

− ··· (5)<br />

Again, using a calcula<strong>to</strong>r, write down the partial sums as decimals (record 6 digits after the<br />

decimal point):<br />

s3 = s6 = s9 =<br />

s4 = s7 = s10 =<br />

s5 = s8 = s11 =<br />

Compare these partial sums <strong>to</strong> the numbers (use your calcula<strong>to</strong>r and write down 6 decimal<br />

places):<br />

e = and<br />

1<br />

e =<br />

The series (5) seems <strong>to</strong> converge and the sum appears <strong>to</strong> be S = .<br />

Problem 7 Consider the series<br />

2 2 2 2 2<br />

+ + + + +<br />

1·3 1 3·3 3 5·3 5 7·3 7 9·3 9<br />

2<br />

+ ··· (6)<br />

11·3 11<br />

whose numera<strong>to</strong>r is always 2 and the denomina<strong>to</strong>rs are successive odd numbers times the same


odd power of 3. This series converges. As before, write the partial sums as decimals <strong>to</strong> 6 places.<br />

S<strong>to</strong>p when you reach a partial sum that is equal <strong>to</strong> the number ln2 = <strong>to</strong> 6 decimal<br />

places.<br />

s1 = s4 = s7 =<br />

s2 = s5 = s8 =<br />

s3 = s6 = s9 =<br />

Problem 8 A famous series is the harmonic series<br />

1 + 1<br />

2<br />

+ 1<br />

3<br />

+ 1<br />

4<br />

+ 1<br />

5<br />

+ 1<br />

6<br />

(a) Use a calcula<strong>to</strong>r <strong>to</strong> find the sum s10 of the first 10 terms.<br />

(b) Go <strong>to</strong> WolframAlpha.com and type in the words<br />

the sum from n=1 <strong>to</strong> n=10 of 1/n<br />

Is that what you got?<br />

1<br />

+ ··· (7)<br />

7<br />

(c) Make a table showing s10,s20,s50,s100 <strong>to</strong> 2 decimal places (e.g. 5.27). Then do some more.<br />

(d) Does the harmonic series converge?<br />

Problem 9 Repeat the above steps for the alternating harmonic series<br />

1 − 1<br />

2<br />

+ 1<br />

3<br />

− 1<br />

4<br />

+ 1<br />

5<br />

− 1<br />

6<br />

(a) Again use a calcula<strong>to</strong>r <strong>to</strong> find the sum s10 of the first 10 terms.<br />

(b) Check your answer on WolframAlpha.com <strong>—</strong> enter<br />

the sum from n=1 <strong>to</strong> n=10 of (-1)^n*1/n<br />

1<br />

+ ··· (8)<br />

7<br />

(c) Again make a table showing s10,s20,s50,s100 <strong>to</strong> 2 decimal places and beyond.<br />

(d) Does the alternating harmonic series converge?

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!