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Geometry Regents at Random Worksheets - JMap

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113 ANS: 4<br />

The slope of 3x + 5y = 4 is m = −A<br />

B<br />

= −3<br />

5 . m ⊥<br />

= 5<br />

3 .<br />

PTS: 2 REF: 061127ge STA: G.G.62 TOP: Parallel and Perpendicular Lines<br />

114 ANS:<br />

R′(−3,−2), S' (−4,4), and T ′(2,2).<br />

PTS: 2 REF: 011232ge STA: G.G.54 TOP: Rot<strong>at</strong>ions<br />

115 ANS:<br />

3a + a − 6<br />

(2a − 3,3b + 2). ,<br />

2<br />

2b − 1 + 4b + 5<br />

<br />

<br />

4a − 6<br />

= ,<br />

<br />

2 2<br />

6b + 4<br />

<br />

<br />

= (2a − 3,3b + 2)<br />

2 <br />

PTS: 2 REF: 061134ge STA: G.G.66 TOP: Midpoint<br />

116 ANS:<br />

The slope of y = 2x + 3 is 2. The slope of 2y + x = 6 is −A<br />

B<br />

lines are perpendicular.<br />

ID: A<br />

−1<br />

= . Since the slopes are opposite reciprocals, the<br />

2<br />

PTS: 2 REF: 011231ge STA: G.G.63 TOP: Parallel and Perpendicular Lines<br />

117 ANS: 4 PTS: 2 REF: 081211ge STA: G.G.5<br />

TOP: Planes<br />

118 ANS: 4<br />

x 2 − 6x + 2x − 3 = 9x + 27<br />

x 2 − 4x − 3 = 9x + 27<br />

x 2 − 13x − 30 = 0<br />

(x − 15)(x + 2) = 0<br />

x = 15, − 2<br />

PTS: 2 REF: 061225ge STA: G.G.32 TOP: Exterior Angle Theorem<br />

119 ANS:<br />

<br />

M<br />

<br />

−7 + 5<br />

2<br />

, 2 + 4<br />

2<br />

<br />

<br />

3 + 5<br />

= M(−1,3). N<br />

<br />

2<br />

, −4 + 4<br />

2<br />

<br />

= N(4,0). MN is a midsegment.<br />

<br />

PTS: 4 REF: 011237ge STA: G.G.42 TOP: Midsegments<br />

120 ANS: 1 PTS: 2 REF: 061125ge STA: G.G.39<br />

TOP: Special Parallelograms

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