Geometry Regents at Random Worksheets - JMap
Geometry Regents at Random Worksheets - JMap
Geometry Regents at Random Worksheets - JMap
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113 ANS: 4<br />
The slope of 3x + 5y = 4 is m = −A<br />
B<br />
= −3<br />
5 . m ⊥<br />
= 5<br />
3 .<br />
PTS: 2 REF: 061127ge STA: G.G.62 TOP: Parallel and Perpendicular Lines<br />
114 ANS:<br />
R′(−3,−2), S' (−4,4), and T ′(2,2).<br />
PTS: 2 REF: 011232ge STA: G.G.54 TOP: Rot<strong>at</strong>ions<br />
115 ANS:<br />
3a + a − 6<br />
(2a − 3,3b + 2). ,<br />
2<br />
2b − 1 + 4b + 5<br />
<br />
<br />
4a − 6<br />
= ,<br />
<br />
2 2<br />
6b + 4<br />
<br />
<br />
= (2a − 3,3b + 2)<br />
2 <br />
PTS: 2 REF: 061134ge STA: G.G.66 TOP: Midpoint<br />
116 ANS:<br />
The slope of y = 2x + 3 is 2. The slope of 2y + x = 6 is −A<br />
B<br />
lines are perpendicular.<br />
ID: A<br />
−1<br />
= . Since the slopes are opposite reciprocals, the<br />
2<br />
PTS: 2 REF: 011231ge STA: G.G.63 TOP: Parallel and Perpendicular Lines<br />
117 ANS: 4 PTS: 2 REF: 081211ge STA: G.G.5<br />
TOP: Planes<br />
118 ANS: 4<br />
x 2 − 6x + 2x − 3 = 9x + 27<br />
x 2 − 4x − 3 = 9x + 27<br />
x 2 − 13x − 30 = 0<br />
(x − 15)(x + 2) = 0<br />
x = 15, − 2<br />
PTS: 2 REF: 061225ge STA: G.G.32 TOP: Exterior Angle Theorem<br />
119 ANS:<br />
<br />
M<br />
<br />
−7 + 5<br />
2<br />
, 2 + 4<br />
2<br />
<br />
<br />
3 + 5<br />
= M(−1,3). N<br />
<br />
2<br />
, −4 + 4<br />
2<br />
<br />
= N(4,0). MN is a midsegment.<br />
<br />
PTS: 4 REF: 011237ge STA: G.G.42 TOP: Midsegments<br />
120 ANS: 1 PTS: 2 REF: 061125ge STA: G.G.39<br />
TOP: Special Parallelograms