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Geometry Regents at Random Worksheets - JMap

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7 ANS:<br />

30.<br />

PTS: 2 REF: 011129ge STA: G.G.31 TOP: Isosceles Triangle Theorem<br />

8 ANS: 3 PTS: 2 REF: 061122ge STA: G.G.56<br />

TOP: Identifying Transform<strong>at</strong>ions<br />

9 ANS: 3<br />

TOP: Solids<br />

PTS: 2 REF: 011105ge STA: G.G.10<br />

10 ANS: 4 PTS: 2 REF: 081106ge STA: G.G.17<br />

TOP: Constructions<br />

11 ANS: 3 PTS: 2 REF: 061220ge STA: G.G.74<br />

TOP: Graphing Circles<br />

12 ANS:<br />

16.7. x 12<br />

=<br />

25 18<br />

18x = 300<br />

x ≈ 16.7<br />

PTS: 2 REF: 061133ge STA: G.G.46 TOP: Side Splitter Theorem<br />

13 ANS:<br />

PTS: 2 REF: 081233ge STA: G.G.19 TOP: Constructions<br />

14 ANS: 2<br />

The slope of a line in standard form is −A<br />

B<br />

ID: A<br />

−4<br />

, so the slope of this line is . A parallel line would also have a slope<br />

3<br />

of −4<br />

. Since the answers are in standard form, use the point-slope formula. y − 2 = −4 (x + 5)<br />

3 3<br />

3y − 6 = −4x − 20<br />

4x + 3y = −14<br />

PTS: 2<br />

15 ANS:<br />

REF: 061123ge STA: G.G.65 TOP: Parallel and Perpendicular Lines<br />

L = 2πrh = 2π ⋅ 12 ⋅ 22 ≈ 1659. 1659<br />

≈ 2.8. 3 cans are needed.<br />

600<br />

PTS: 2 REF: 061233ge STA: G.G.14 TOP: L<strong>at</strong>eral Area

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