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Geometry Regents at Random Worksheets - JMap

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161 ANS: 3<br />

8<br />

2<br />

= 12<br />

x<br />

8x = 24<br />

x = 3<br />

.<br />

PTS: 2 REF: 061216ge STA: G.G.46 TOP: Side Splitter Theorem<br />

162 ANS: 1<br />

Parallel lines intercept congruent arcs.<br />

PTS: 2 REF: 061105ge STA: G.G.52 TOP: Chords<br />

163 ANS: 3 PTS: 2 REF: 081227ge STA: G.G.42<br />

TOP: Midsegments<br />

164 ANS:<br />

11. x 2 + 6x = x + 14.<br />

6(2) − 1 = 11<br />

x 2 + 5x − 14 = 0<br />

(x + 7)(x − 2) = 0<br />

x = 2<br />

PTS: 2<br />

165 ANS: 4<br />

REF: 081235ge STA: G.G.38 TOP: Parallelograms<br />

25 2 2 <br />

26 − 12 <br />

−<br />

<br />

2<br />

<br />

= 24<br />

ID: A<br />

PTS: 2 REF: 011219ge STA: G.G.40 TOP: Trapezoids<br />

166 ANS: 2<br />

TOP: Planes<br />

PTS: 2 REF: 011109ge STA: G.G.9<br />

167 ANS:<br />

−6 + 2<br />

m AB = ,<br />

2<br />

−2 + 8<br />

<br />

<br />

2 <br />

= D(2,3) m <br />

2 + 6 8 + −2 <br />

BC = , = E(4,3) F(0,−2). To prove th<strong>at</strong> ADEF is a<br />

2 2 <br />

parallelogram, show th<strong>at</strong> both pairs of opposite sides of the parallelogram are parallel by showing the opposite<br />

3 − −2 5<br />

sides have the same slope: m AD = = AF DE because all horizontal lines have the same slope. ADEF<br />

−2 − −6 4<br />

3 − −2 5<br />

mFE = =<br />

4 − 0 4<br />

is not a rhombus because not all sides are congruent. AD = 5 2 + 4 2 = 41 AF = 6<br />

PTS: 6 REF: 081138ge STA: G.G.69 TOP: Quadril<strong>at</strong>erals in the Coordin<strong>at</strong>e Plane

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