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Mathematical Literacy P 2 Memorandum September 2012
MATHEMATICAL
LITERACY PAPER 2
Preparatory Examination 2012
MEMORANDUM
This memorandum consists of 9 pages
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Mathematical Literacy P 2 Memorandum September 2012
NOTE
Read the following instructions carefully:
If a candidate answers a question TWICE, only mark the FIRST attempt.
If a candidate has crossed out an attempt of a question and not redone the
question, mark the crossed out version.
Consistent accuracy applies in ALL aspects of the marking memorandum.
Symbol Explanation Verduideliking
M Method Metode
MA Method with Accuracy Metode met akkuraatheid
CA Consistent accuracy Deurlopende Akkuraatheid
A Accuracy (Answer) Akkuraatheid / Andwoord
C Conversion Omskakeling / Herleiding
S Simplification Vereenvoudiging
RT / RG / RM Reading from Table/Graph/Map Lees vanaf ‘n Tabel / Grafiek / Kaart
F Choosing the correct formula Keuse van formule
SF Substitution in formula Korrekte vervanging in ‘n formule
O Opinion Opinie / voorbeeld
R Rounding off / Reason Afronding / Rede
P Penalty e.g. no units, ect Penalisering bv. Eenhede weggelaat
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Mathematical Literacy P 2 Memorandum September 2012
QUESTION 1 [31 Marks]
No Calculations / workings
1.1.1 Basic Salary(A) = R 16 821,75 - R 800,00 √
= R 16 021,75 √ (2)
1.1.2 Annual basic salary(B) = R 16 021,75 x 12 √
= R 192 261,00 √ (2)
1.1.3 Total deductions (C) = R 2 091,86 + R 1 201,63 + R 546,00
= R 3 839,49
Net salary (D) = R 16 821,75 - R 3 839,49 √
= R 12 982,26 √ (2)
1.2.1 Yearly taxable income
= R 28 800 + 25% of (amount above R 160 000) - tax rebates
= R 28 800 + 25% x (R 201 861 - R 160 000) – R 11 440 √√√
= R 28 800 + 0,25 x R 41 861 - R 11 440
= R 28 800 + R 10 465,25 - R 11 440 √
= R 27 825,25 √
Monthly income tax =
√
= R 2 318,77 √ (7)
1.2.2 No, only R 2 091,86 tax was deducted instead of
R 2 318,77√√ (2)
1.3.1 R 4 999 = 114% √ OR 1,14 . = R 4 999 √
= 1% = √
R 43,8509 = 1% √
R 4 385,09 = 100% √ = R 4 385,09 √ (3)
1.3.2 On terms = R 500,00 + ( R 189,00 x 36 ) √
= R 500,00 + R 6 804,00 √
= R 7 304,00 √ (3)
1.3.3 A = R 4 999,00 ( 1 - 0,2) 5 √√√
= R 1 638,07 √ (5)
1.4 Total area = (L x B) + (
x
= (50cm x 60cm) +
x 3,14 x 30cm √√√
= 300cm 2 + 1 413cm 2 √
= 1 713cm 2 √ (5)
Marks /
commen
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tttts
M: 1
A: 1
M: 1
A: 1
M: 1
A: 1
SF: 3
S: 1
A: 1
M: 1
A: 1
A: 1
R: 1
M:2
A: 1
M: 1
S: 1
A: 1
SF: 3
A: 2
SF: 3
S: 1
A: 1
AS LEVEL
12.1.1 2
12.1.1 2
12.1.1 2
12.1.3 4
12.1.3 4
12.1.3 3
12.1.1 2: 2 marks
&
3: 1 mark
12.1.3 4
12.3.3 3: 3 marks
&
4: 2 marks

Mathematical Literacy P 2 Memorandum September 2012
QUESTION 2 [25 Marks]
NO Calculations Mark
comment
2.1 Veranda: 1,5m x 4m √√√ (3) A: 3
2.2.1 Bathroom = 2,5m x 4m = 10m 2 √
Kitchen = 3m x 4m = 12m 2 √
Veranda = 1,5m x 4m = 6,0m 2 √
Total area to be tiled = 6m 2 + 12m 2 + 10m 2
2.2.2 28m 2 + 2m 2 = 30m 2 √
√
= 22 boxes of tiles √
= 28m 2 √ (4)
Cost of tiles = 22 boxes x R 169,95 / box √
= R 3 738,90 √
Yes Ms Olivier budget of R 3 800 is correct √ (6)
2.3 Total area = 12m 2 + 16m 2 = 28m 2
Cost for under carpet = 28m 2 x R 45,99 / m 2 √
= R 1 287,72 √
OR:
Cost of carpets =28m 2 x R209,00/m 2 √ 28 (R209+R45,99)/
= R 5 852,00 √ = R 7 139,72
2.4
Total cost for carpeting = R 7 139,72 √ (5)
Total cost for fittings = R 3 999 + (3 x R 739) + R 789 √√√
= R 3 999 + R 2 217 + R 789 √
= R 7 005 √
Yes ms Olivier can afford to put in the gas stove because
she has R 995 left of R 8 000 √√ (7)
AS LEVEL
12.3.1 3
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M: 3
A: 1
Adding:
1
M: 1
A: 1
Adding:
1
M: 1
S: 1
M: 1
S: 1
A: 1
M: 3
S: 1
A: 1
A: 1
R: 1
12.3.1 3
12.3.1 4
12.3.1 3
12.1.1
12.1.2
4

Mathematical Literacy P 2 Memorandum September 2012
QUESTION 3 [34 Marks]
No Calculations Mark
comment
3.1.1 C 2 √ OR (1) A: 1
3.1.2 North Westerly √ (2)
3.1.3 4cm represents 500m
1cm : 125 m √
15,5 cm as the crow fly √ OR
(15,5 x 125)m √ (16 x 125)m
= 1937,5 m = 2 000m
2km √ = 2km (4)
3.1.4 3cm x 3cm
= 3 x 125m x 3 x 125m √
= 375m x 375m √
= 140 625m 2 √ (3)
3.1.5 11 squares (2)
3.1.6 11 x 140 625m 2 √
= 1 546 875m 2 √
= 1,546875km 2
1,5km 2 √ (3)
3.2.1 HIGHEST - 1956 √
Difference: 500 - 150 √
= 350 √ (3)
3.2.2 1963; 1969; 1984; 1988 √√√√ (Allow ± 1 year) (4)
3.2.3 1963 to 1969 and √√ (Allow ± 1 year)
1984 to 1988 √√ (4)
3.3.1 Windscreen wipers √ (1)
3.3.2
3.3.3
x 1000 √
= 100 √ (2)
or 0,8 or 80% √ (1)
3.3.4 Annexure A (4)
AS LEVEL
12.3.4 2
A: 2 12.3.4 2
S: 1
(between
15cm and
16cm): 1
M: 1
A: 1
12.3.2
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M: 2
A: 1
12.3.2
3
3
A: 2 12.3.1 3
M: 1
S: 1
A:1
A: 1
M: 1
A: 1
12.3.2 3
12.4.1 3
A: 4 12.4.1 4
A: 4 12.4.2 3: 2 marks
&
4: 2 marks
A: 1 12.4.5 2
M: 1
A: 1
12.4.5 2
A: 1 12.4.5 2
12.4.5 3

Mathematical Literacy P 2 Memorandum September 2012
QUESTION 4 [24 Marks]
No Calculations Mark
Comment
4.1.1
(a)
False. At least 25 % of the learners who wrote the test from
School A did not get any answers correct. √√ (2)
(b) True. The median is 67%. This means that at least half the
learners scored 67% or more. So, at least half the learners
passed the test. √√ (2)
(c) True. Range = maximum mark - minimum mark = 65 for
both schools. √√ (2)
(d) True. The median is 67%. This means that at least half the
learners scored 67% or more. So, at least half of 180 (90
learners) got 67%. √√ (2)
(e) False. The 50 th percentile is the median. The median for
School B is 67% and no learner from School A scored above
65%. √√ (2)
4.2(a) Histogram 4. The 1 st quartile is 0, which means that 50
learners must got 0. √√√ (3)
4.2(b) Histogram 2. The minimum mark at School B was 35. √√√(3)
AS LEVEL
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A: 1
R: 1
A: 1
R: 1
A: 1
R: 1
A: 1
R: 1
A: 1
R: 1
A: 1
R: 2
A: 1
R: 2
12.4.1 4
12.4.1 4
12.4.1 3
12.4.1 4
12.4.1 4
12.4.3 4
12.4.3 4
4.3.1
(a)
B √√ (2) A: 2 12.2.2 2
(b) C √√ (2) A: 2 12.2.2 2
(c) D √√ (2)
(d) A √√ (2)
A: 2 12.2.2 2
A: 2 12.2.2 2

Mathematical Literacy P 2 Memorandum September 2012
QUESTION 5 [24 Marks]
No Calculations Mark
comment
5.1 Amount of postage (Method A) = R 24,36 + (4 x R 3,28) √√
= R 37,48 √ (3)
5.2 Cost per Courier = R 45 √ (1)
5.3.1 C = 24,36 + 3,28(n-1) √√ (2)
5.3.2 A = R 24,36 + (29 x R 3,28) = R 119,48 √√√
B = R 45 + R 10 = R 55 √√
C = R 45 + (R 2 x R 10) = R 65 √√ (7)
5.3.3 Annexure B (7)
5.3.4 Method B (Courier service) (1)
5.3.5 Small parcels less than 7,5kg use method A √
Parcels more than 8kg method B √√ (3)
M: 2
A: 1
AS LEVEL
12.1.1 3
A: 1 12.1.1 2
A: 2 12.2.3 3
M: 4
A: 3
12.2.1 3
12.2.4 3
A: 2 12.2.2 4
R: 3 12.2.4
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4

Mathematical Literacy P 2 Memorandum September 2012
Question 6 [12 Marks]
6.1.1
6.1.2
6.1.3
6.2
Between 27 July and 04 Augustus 2008 √√ (2)
RG: 2 12.2.3 3
The exchange rate was stable √√ (2) O: 2 12.2.3 3
R 18 125,00 = $(
) √√
= $ 2 196,97 √
= $ 2 197 , Yes he received the right
amount √ (4)
* As the Rand further weakens against the Dollar he
would get more if he change his Dollars against the Rand √
* As a frequent traveller to the US he would always need
Dollars therefore rather keep it √√
* It’s better not to change currencies, as he would have to
spend money each time he changes, on bank charges √√
OR 2 any logical answers (4)
BLOOM’s TOXONOMY LO’s
MA: 2
CA: 1
R: 1
O: 2
O: 2
Any 2
reasons
Level 1 - 0 marks - 0% LO 1 - 41 marks - 27%
Level 2 - 24 marks - 16% LO 2 - 36 Marks - 24%
Level 3 - 64 marks - 43% LO 3 - 38 Marks - 25%
Level 4 - 62marks - 41% LO 4 - 35 Marks - 23%
TOTAL : 150 marks
12.1.3 4
12.2.3 4
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Mathematical Literacy P 2 Memorandum September 2012
Question 3.3.4 - Tree diagram
First car checked Second car checked
(
Faulty brakes
Good brakes
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(
(
(
)Faulty brakes √
Good brakes √
Faulty brakes √
) Good brakes √

Mathematical Literacy P 2 Memorandum September 2012
Question 5.3.2
`
Cost (R)
200
180
160
140
120
100
80
60
40
20
Three marks for Method A √ √ √
Three marks for Method B √ √ √
Relationship between the cost of sending
a parcel and the number of kilogram per parcel
5 10 15 20 25 30 35 40
Number of kilograms (kg)
Option A
Option B
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