\fdO'^ - Old Forge Coal Mines

ARITHMETIC. 7
If the tools are worth twice as much as the building, plus
11,875, then the tools are worth
$10938
2
plus
21876
18 7 5
$23751 = value of tools.
Value of building = $10938
Value of tools = 2 3 7 51
$34689 = value of the building
and tools, {a) Ans.
Value of engine and
boiler = $3246
Value of building
and tools = 3 4 6 8 9
$ 3 7 9 3 5 = value of the whole
plant, (d) Ans.
(18) {a) (72 X 48 X 28 X 5) -i- (96 X 15 X 7 X 6).
Placing the numerator over the denominator the problem
becomes
72 X 48 X 28 X 5 _~
96 X 15 X 7 X 6
The 5 in the dividend and 15 in the divisor are both divis-
ible by 5, since 5 divided by 5 equals 1, and 15 divided by
5 equals 3. Cross off the 5 and write the 1 over it ; also cross
off the 15 and write the 3 tinder it. Thus,
1
72 X 48 X 28 X ^ _
96 X ;^ X 7 X 6 ~
3
The 5 and 15 are not to be considered any longer, and, in
fact, may be erased entirely and the 1 and 3 placed in their
stead, and treated as if the 5 and 15 never existed. Thus,
72 X 48 X 28 X 1 _
96 X 3 X 7 X 6