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\fdO'^ - Old Forge Coal Mines

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184 ELEMENTARY MECHANICS.<br />

(d) Using formula 18,/<br />

sec, = -035995 min., the time of falling<br />

37,500<br />

33,000 X .035995<br />

2X 75<br />

^=i/'t 32.16 = 2.1597<br />

(437) 127 ^62.5 = 2.032 = specific gravity. Ans.<br />

(438)<br />

62.5<br />

1,728<br />

Use i<br />

(439) Use formula 21. W=(^^\<br />

2 X 60X 6.5<br />

or<br />

X .48 = 499.2 lb. Ans. See ^'<br />

6.5-5.75<br />

Fig. 37.<br />

(440)<br />

X 9. 823 = .35529 lb. Ans. ^<br />

See Art. 961.<br />

77., /3 io\ ^^' 1.5X25'<br />

^x(8^^^) = -2-7=^^r32:i6'"^<br />

1.5 X 25'<br />

/r=!^ii!dr' = 406.42 lb. Ans.<br />

f H- 12<br />

(441 ) (a) 2,000 -^ 4 = 500 = wt. of cu.<br />

ft. 500 -j- 62.5 = 8 = specific gravity. Ans.<br />

500 = .28935 lb. Ans.<br />

Fig. 38.<br />

J7<br />

Fig. 37.<br />

m'<br />

(442) See Fig. 38. 14.5 X 2<br />

= 29. 30X 29= J>rx 5, or W^ =<br />

= 30X29 • _ . ., .<br />

5<br />

174 lb. Ans.<br />

(443) 75 X .21 = 15.75 lb.<br />

(444) (a) 900 X 150 = 135,000 ft. -lb. Ans,<br />

= 9,000 ft. -lb. per min. Ans.<br />

135,000<br />

15<br />

(^)A2!E = iH.p<br />

33,000 11<br />

Ans<<br />

2><br />

Ans.

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