\fdO'^ - Old Forge Coal Mines

38 ARITHMETIC.
nominator of the fraction. The problem
^_> ~ • 5?-l^l-lxZ?-ior 5 Ans
3^ ^ ~ 32 •
16 ~ ^^ ^ ~ '
^ 2
16 16 2
is now reduced to
1.25 X 20 X 3 _ In this problem 1.25 X 20 X
*
(74) 87 + (11 X 8) 3 constitutes the numerator of
459 + 32 the complex fraction.
1.2 5 Multiplying the factors of the numerator
X 2 together, we find their product to be 75.
2 5.0
X_3
75
The fraction — /I} ,
the complex
87 4- (11 X 8^
^^
4o9 + 32
' constitutes the denominator of
fraction. The value of the numerator of this
fraction equals 87 + 88 = 175.
The numerator is combined as though
87 + (11 X 8), and its result is
11
88
+ 87
175
8 times
it were written
The value of the denominator of this fraction is equal to
459 + 32 = 491. The problem then becomes
3
75 _ 75. 175 75^491 ;^ x 491 _ 1,473 „^.3 ,^
491
(75) 1 plus .001 = 1.001. .01 plus .000001 = .010001.
And 1.001 - .010001 =
1.001
.010001
7
.990999 Ans.