\fdO'^ - Old Forge Coal Mines

180 ELEMENTARY MECHANICS.
a distance from C^, according to formula 20 (Art. 911)
8X , ^ C^C, 8 X 8.013 .
,, ^ ^ O.I •
= = -^^1 ^"- ^. ^= -341 m.
"^"^^ '^ ^80 + 8^ 188
BC=BC^- C^C=d.89S - .34:1 = 0. 557 inches. Ans.
(423) (^) In one revolution the power will have moved
through a distance of 2 X 15 X 3.1416 = 94.248', and the
1"
weight will have been lifted .
j
The
94.248 H-^ = 376.992.
4
37G.992 X 25 = 9,424.8 lb. Ans.
{a) 9,424.8 - 5,000 = 4,424.8 lb. Ans.
{c) 4,424.8 -^ 9,424.8 = 46.95^. Ans..
(424)
See Arts. 920 and 922.
velocity ratio is then
(425) Construct the prism ABED, Fig. 33. From
£, draw the line £ F. Find the center of gravity of the
Horizontal G
Fig. 83.
rectangle, which is at C,, and that of the triangle, which is
i