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Polyharmonic boundary value problems

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2.2 Higher order Sobolev spaces 29<br />

(u,v)H m 0 :=<br />

⎧ <br />

⎪⎨ ∆<br />

Ω<br />

⎪⎩<br />

k u ∆ k vdx if m = 2k,<br />

<br />

∇(∆<br />

Ω<br />

k u) · ∇(∆ k v)dx if m = 2k + 1,<br />

(2.10)<br />

and the corresponding norm<br />

uH m 0 :=<br />

⎧<br />

⎨ ∆ k uL2 if m = 2k,<br />

⎩<br />

∇(∆ k u)L2 if m = 2k + 1.<br />

(2.11)<br />

For general p ∈ (1,∞), one has the choice of taking the Lp-version of (2.11) or the<br />

equivalent norm<br />

:= D m uLp. u W m,p<br />

0<br />

Thanks to these norms, one may define the above spaces in a different way.<br />

Theorem 2.1. If Ω ⊂ R n is a bounded domain, then<br />

W m,p<br />

0 (Ω) = the closure of C∞ c (Ω) with respect to the norm .W m,p<br />

= the closure of C∞ c (Ω) with respect to the norm . m,p<br />

W .<br />

0<br />

Theorem 2.1 follows by combining interpolation inequalities (see [1, Theorem<br />

1,p<br />

4.14]) with the classical Poincaré inequality ∇uLp ≥ cuLp for all u ∈ W0 (Ω).<br />

If Ω is unbounded, including the case where Ω = Rn , we define<br />

u D m,p (Ω) := D m u L p (Ω),<br />

D m,p (Ω) := the closure of C ∞ c (Ω) with respect to the norm .D m,p,<br />

and, again, let W m,p<br />

0 (Ω) denote the closure of C∞ c (Ω) with respect to the norm<br />

.W m,p. In this unbounded case, a similar result as in Theorem 2.1 is no longer true<br />

since although W m,p<br />

0 (Ω) ⊂ D m,p (Ω), the converse inclusion fails. For instance, if<br />

Ω = Rn , then W m,p<br />

0 (Rn ) = W m,p (Rn ), whereas the function u(x) = (1 + |x| 2 ) (1−n)/4<br />

belongs to D 1,2 (Rn ) but not to H1 0 (Rn ) = H1 (Rn ).<br />

Theorem 2.1 states that, when Ω is bounded, the space Hm 0 (Ω) is a Hilbert space<br />

when endowed with the scalar product (2.10). The striking fact is that not only<br />

all lower order derivatives (including the derivative of order 0!) are neglected but<br />

also that some of the highest order derivatives are dropped. This fact has a simple<br />

explanation since<br />

(u,v)H m 0 =<br />

<br />

D<br />

Ω<br />

m u · D m vdx for all u,v ∈ H m 0 (Ω). (2.12)<br />

One can verify (2.12) by using a density argument, namely for all u,v ∈ C ∞ c (Ω).<br />

And with this restriction, one can integrate by parts several times in order to obtain<br />

(2.12). The bilinear form (2.10) also defines a scalar product on the space D m,2 (Ω)<br />

whenever Ω is an unbounded domain. We summarise all these facts in

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