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Perturbative and non-perturbative infrared behavior of ...

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D 2<br />

U D 2 φ<br />

D 2<br />

Figure 3.1: New vertices proportional to the external U superfield<br />

D 2<br />

U<br />

D 2<br />

D 2<br />

3.1. Superspace approach<br />

To compute quantum corrections at a given loop, we write down all the Feynman diagrams up<br />

to the given order <strong>and</strong> insert an extra ¯ D 2 (D 2 ) derivative on each chiral (antichiral) line leaving<br />

a vertex except for one <strong>of</strong> the lines at a completely (anti)chiral vertex.<br />

The loop integrals are evaluated in the dimensional regularization (n = 4 − 2ǫ) <strong>and</strong> minimal<br />

subtraction scheme. Divergent integrals are regularized using the so-called G-scheme<br />

<br />

d 4 <br />

kf(k) → G(ǫ) d n kf(k) (3.1.7)<br />

where G(ǫ) = (4π) −ǫ Γ(1 − ǫ). Factors <strong>of</strong> 4π are always neglected along the calculations <strong>and</strong> a<br />

(4π) 2 factor is inserted for each momentum loop in the final result.<br />

3.1.2 One-loop divergencies<br />

At one loop divergencies appear that involve the two-, three-, <strong>and</strong> four point functions. The last<br />

two ones are due to the deformation <strong>of</strong> the theory <strong>and</strong> also contain the spurion superfield.<br />

The divergent two-point function is the ordinary self-energy diagram which gives the wave<br />

function renormalization. Its contribution is<br />

A0 → 2<br />

ǫ g¯g<br />

<br />

d 8 zΦ ¯ Φ (3.1.8)<br />

No divergencies with more than one insertion <strong>of</strong> the U vertices can appear; then, the only<br />

divergent topologies are the ones given in Fig. 3.2.<br />

The result for the self-energy momentum integral is<br />

<br />

d 4 k<br />

1<br />

(k 2 + m ¯m)[(p − k) 2 + m ¯m]<br />

→ 1<br />

ǫ<br />

with which one obtain the results<br />

A1 → − 1<br />

ǫ g2 ¯m 2<br />

<br />

d 8 zU(D 2 Φ) 2 = − 1<br />

ǫ g2 ¯m 2 C 2<br />

<br />

A2 → − 4<br />

ǫ g2 <br />

¯g ¯m d 8 zU(D 2 Φ) 2¯<br />

4<br />

Φ = −<br />

ǫ g2¯g ¯mC 2<br />

<br />

A3 → − 4<br />

ǫ g2¯g 2<br />

<br />

d 8 zU(D 2 Φ) 2¯ 2 4<br />

Φ = −<br />

ǫ g2¯g 2 C 2<br />

<br />

d 4 x F 2<br />

d 4 xF 2 ¯ φ<br />

d 4 xF 2 ¯ φ 2<br />

(3.1.9)<br />

(3.1.10)<br />

17

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