A Course on Large Deviations with an Introduction to Gibbs Measures.
A Course on Large Deviations with an Introduction to Gibbs Measures.
A Course on Large Deviations with an Introduction to Gibbs Measures.
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Yet some more<br />
generalities<br />
4.1. C<strong>on</strong>tracti<strong>on</strong> principle<br />
Chapter 4<br />
Sometimes the problem at h<strong>an</strong>d c<strong>an</strong> be formulated as a mapping of <strong>an</strong>other<br />
problem <strong>on</strong> a different space. It is reas<strong>on</strong>able that <strong>an</strong> LDP for the latter<br />
tr<strong>an</strong>sfers <strong>to</strong> <strong>on</strong>e for the former <strong>with</strong> the rate functi<strong>on</strong> at point y being the<br />
smallest value of the original rate functi<strong>on</strong> at preimages of y. This is what<br />
the c<strong>on</strong>tracti<strong>on</strong> principle (or push-forward principle) is about.<br />
C<strong>on</strong>tracti<strong>on</strong> principle. Suppose f is a c<strong>on</strong>tinuous functi<strong>on</strong> from X <strong>to</strong> Y,<br />
two Hausdorff <strong>to</strong>pological spaces, <strong>an</strong>d LDP(µn, rn, I) holds <strong>on</strong> X . Define<br />
νn = µn ◦ f −1 ∈ M1(Y); i.e. νn(A) = µn(f −1 (A)). Define also<br />
J(y) = inf<br />
f(x)=y I(x),<br />
<strong>with</strong> the c<strong>on</strong>venti<strong>on</strong> that the inf over <strong>an</strong> empty set is infinite. Let J be the<br />
lower semic<strong>on</strong>tinuous regularizati<strong>on</strong> of J. That is,<br />
<br />
<br />
J(y) = sup inf J : y ∈ G, G is open .<br />
G<br />
(a) LDP(νn, rn, J) holds <strong>on</strong> Y.<br />
(b) If I is tight, then J ≡ J is tight as well.<br />
Proof. By Lemma 2.13 it suffices <strong>to</strong> prove that J satisfies the large deviati<strong>on</strong><br />
bounds (2.3) <strong>an</strong>d (2.4). Take a closed set F ⊂ Y. Then<br />
lim<br />
n→∞<br />
1<br />
rn<br />
log µn(f −1 (F )) ≤ − inf<br />
x∈f −1 I(x) = − inf<br />
(F ) y∈F inf I(x) = − inf<br />
f(x)=y y∈F<br />
J(y).<br />
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