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Asymptotic behaviour of the Kazdan-Warner solution in the annulus ∗

Asymptotic behaviour of the Kazdan-Warner solution in the annulus ∗

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and for N = 2,<br />

Ga,b(r, s) =<br />

s<br />

log b − log a<br />

⎧<br />

⎪⎨ (log r − log a)(log b − log s) for a < r ≤ s<br />

⎪⎩<br />

(log s − log a)(log b − log r) for s < r < b<br />

(2.26)<br />

Pro<strong>of</strong> <strong>of</strong> Corollary 1.2 It is enough to compare directly <strong>the</strong> function ω <strong>in</strong><br />

Theorem 1.1 with <strong>the</strong> function Ga,b(r, r0). ⊓⊔<br />

3 The ”local” convergence result<br />

Let us beg<strong>in</strong> this section with <strong>the</strong> follow<strong>in</strong>g classification result,<br />

Proposition 3.1. All <strong>the</strong> <strong>solution</strong> <strong>of</strong> <strong>the</strong> problem<br />

are given by<br />

with α and y real constants.<br />

− z ′′ = e z <strong>in</strong> R (3.1)<br />

Uα,y(r) = log 4α2 e √ 2(αr+y)<br />

(1 + e √ 2(αr+y) ) 2<br />

Pro<strong>of</strong>. It is a straightforward computation. ⊓⊔<br />

Let us consider <strong>the</strong> function<br />

with up(rp) = ||up||∞ and pε 2 p<br />

p<br />

ũp(r) = (up(εpr + rp) − ||up||∞) (3.2)<br />

||up||∞<br />

p−1 ||up|| ∞ = 1.<br />

We have that ũp solves <strong>the</strong> problem<br />

⎧<br />

⎪⎨ −ũ ′′<br />

p − N−1<br />

εpr+rp εpũ ′ <br />

p = 1 + ũp<br />

p p<br />

⎪⎩<br />

ũp(0) = ũ ′ p<br />

(0) = 0,<br />

<strong>in</strong><br />

a−rp<br />

In <strong>the</strong> next proposition we study <strong>the</strong> limit <strong>of</strong> <strong>the</strong> function ũp.<br />

Proposition 3.2. We have that<br />

√<br />

2r<br />

4e<br />

where U(r) = log<br />

(1+e √ 2r ) 2<br />

εp<br />

<br />

b−rp<br />

, εp<br />

(3.3)<br />

ũp → U uniformly <strong>in</strong> C 1 loc(R) (3.4)<br />

is <strong>the</strong> only <strong>solution</strong> <strong>of</strong> <strong>the</strong> problem.<br />

⎧<br />

⎪⎨ −z ′′ = ez <strong>in</strong> R<br />

⎪⎩<br />

z(0) = z ′ (0) = 0<br />

9<br />

(3.5)

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