Pre-Calculus Parametrics Worksheet #2
Pre-Calculus Parametrics Worksheet #2
Pre-Calculus Parametrics Worksheet #2
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Parametric Equations Name<br />
1. Fill in the table and sketch the parametric equation for t [-2,6]<br />
x = t 2 + 1<br />
y = 2 – t<br />
t x y<br />
-2<br />
-1<br />
0<br />
1<br />
2<br />
3<br />
4<br />
5<br />
6<br />
<br />
<br />
<br />
<br />
<br />
<br />
<br />
Problems 2 – 6: Eliminate the parameter to write the parametric equations as a<br />
rectangular equation.<br />
2. x = 6 – t 3. x = ½t + 4 4. x = 3 cos t<br />
y = 3t - 4 y = t 3 y = 3 sin t<br />
5. x = cos t 6. x = 4 + 2 cos t<br />
y = 2 sin 2 t y = -1 + 4 sin t<br />
Problems 7 and 8: Write two new sets of parametric equations for the following<br />
rectangular equations.<br />
7. y = (x + 2) 3 – 4 8. x = y 2 - 3<br />
<br />
<br />
<br />
<br />
<br />
y<br />
x
9. For the parametric equations x = t and y = t 2<br />
a) Sketch the graph and state an appropriate window.<br />
b) Graph x = t – 1 and y = t 2 . How does this compare to the graph in part (a)?<br />
c) Graph x = t and y = t 2 – 3. How does this compare to the graph in part (a)?<br />
d) Write parametric equations which will give the graph in part (a) a vertical stretch by<br />
a factor of 2 and move the graph 5 units to the right. (Hint: Verify on your<br />
calculator!)<br />
Problems 10-11: Write a new set of parametric equations with the following<br />
transformations for x = t 4 – 3 and y = 2t .<br />
10. Shift up 7 and horizontally 11. Shift left 3 and<br />
stretched by a factor of 4 shift down 5<br />
12. For the curve (x + 5) 2 + y 2 = 4 complete the following:<br />
a) Write a pair of parametric equations for the curve.<br />
b) Give an appropriate window and sketch the graph.<br />
c) How could you graph just the top half of the curve?<br />
d) How could you graph just the left side of the curve?<br />
13. Do the following sets of parametric equations cross or intersect? Justify your<br />
answer.<br />
a) x1 = 3 – t and x2 = t + 19<br />
y1 = t 2 – 60 y2 = t + 12<br />
b) x1 = 3 – t and x2 = 3 – 2t<br />
y1 = 2t + 1 y2 = 2 + 3t