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Linear Matrix Inequalities in Control

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Why are LMI’s <strong>in</strong>terest<strong>in</strong>g?<br />

Reason 4: conversion nonl<strong>in</strong>ear constra<strong>in</strong>ts to l<strong>in</strong>ear ones<br />

Theorem (Schur complement)<br />

Let F be an aff<strong>in</strong>e function with<br />

<br />

F11(x)<br />

F (x) =<br />

F21(x)<br />

<br />

F12(x)<br />

,<br />

F22(x)<br />

F11(x) is square.<br />

Then<br />

F (x) ≺ 0 ⇐⇒<br />

⇐⇒<br />

<br />

F11(x) ≺ 0<br />

F22(x) − F21(x) [F11(x)] −1 F12(x) ≺ 0.<br />

<br />

F22(x) ≺ 0<br />

F11(x) − F12(x) [F22(x)] −1 F21(x) ≺ 0<br />

Siep Weiland and Carsten Scherer (DISC) <strong>L<strong>in</strong>ear</strong> <strong>Matrix</strong> <strong>Inequalities</strong> <strong>in</strong> <strong>Control</strong> Class 1 47 / 59<br />

.

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